Answer:
x + 3 = 0.
Step-by-step explanation:
One would be:
x + 3 = 0 Subtract 3 from both sides:
x + 3 - 3 = 0 - 3
x = -3
18 inches sqa-wared. "Nailed it!"
Answer:
-6<x<-9
Step-by-step explanation:
if x+9<0 and 2x>-12
x<-9
x>-6
X is smaller than -9 but greater than -6.
The solution is -6<x<-9
Answer:
roots : 4, -4, i, -i
Step-by-step explanation:
This gets a bit tricky.
We have to substitude x^2 as u in this problem.
Now to rewrite x^4 − 15x^2 − 16 = 0 with u, we get
u^2 - 15u - 16 = 0
( u - 16) (u + 1)
U = 16
U = -1
<em>This is not the end of the problem. </em>
Now we have to substitute x^2 back to u.
x^2 = 16 --> we get the roots 4 and -4
x^2 = -1 --> we get the roots i and -i
tadah!