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3 years ago

Solve the equation for x. a. -10 b. 1 c. 1/10 d. -1

Mathematics

2 answers:

Olin [163]3 years ago

5 0

Answer:

$x=-1$

Step-by-step explanation:

$6x(1/3)-15(1/3)=10x(1/2)-4(1/2)$

$6/3x-15/3=10/2x-4/2$

$2x-5=5x-2$

$-5+2=5x-2x$

$-3=3x$

$-3/3=x$

$-1=x$

Mashcka [7]3 years ago

3 0

Answer:

2x - 5 = 5x - 2

3x = -3

x=-1

Step-by-step explanation:

Your welcome!!

Brainliest Please!!!

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3 years ago

Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?

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$Perimeter=19.9units$

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle, and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

$d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units$

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$d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units$

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$d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units$

Now, calculating the perimeter, we have:

$Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units$

Have a nice day!

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