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Simora [160]
2 years ago
11

SOLVE x^4 − 15x^2 − 16 = 0 What are the roots of the equation?

Mathematics
1 answer:
kakasveta [241]2 years ago
8 0

Answer:

roots : 4, -4, i, -i

Step-by-step explanation:

This gets a bit tricky.

We have to substitude x^2 as u in this problem.

Now to rewrite x^4 − 15x^2 − 16 = 0 with u, we get

u^2 - 15u - 16 = 0

( u - 16) (u + 1)

U = 16

U = -1

<em>This is not the end of the problem. </em>

Now we have to substitute x^2 back to u.

x^2 = 16  --> we get the roots 4 and -4

x^2 = -1 --> we get the roots i and -i

tadah!

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Start with the second question. If you divide 36 by 2, you get 18 which is the value for the triangle. Now since you know the value of the triange you subtract it from 45. (45-18=27) 27 is the value of the circle. Lastly, subtract 27 from 53 to get the value of the square (53-27=26). Hope this helps!

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3 years ago
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3 years ago
May someone help me with this question please anyone please
djverab [1.8K]
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