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chubhunter [2.5K]
3 years ago
8

Round 607.5 to the nearest whole number.

Mathematics
2 answers:
kari74 [83]3 years ago
7 0
608

607.5

.5 rounds up to 1

607+1=608
kompoz [17]3 years ago
6 0

Answer:

608

Step-by-step explanation:

607.5 on a number line would be round 608

because 5 is rounded to 10  like that

Apply sam technique

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A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 memb
GrogVix [38]

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say t_{1}, for first program can be written in equation form as,

t_{1} =35+5c,  here c is the no. of classes.

Similarly, the total cost say t_{2} , for second program can be written in equation form as,

t_{2} =10c.

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

t_{1} =t_{2}

35+5c=10c\\10c-5c=35\\5c=35\\c=7

Hence for 7 of classes the programs cost the same.

For more details follow the link:

brainly.com/question/4042361

3 0
2 years ago
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krok68 [10]
The answer is b (-2 5/6)
6 0
3 years ago
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hoa [83]

Answer:

OOF I MEANT A

Step-by-step explanation:

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3 years ago
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7 0
3 years ago
Solve rational inequality x²+x-6/x²-3x-4≤0?​
Fittoniya [83]

Answer:

Step-by-step explanation:

x

2

+

x

−

6

=

(

x

+

3

)

(

x

−

2

)

x

2

−

3

x

−

4

=

(

x

−

4

)

(

x

+

1

)

Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:

x

=

−

3

,

−

1

,

2

,

4

Note that when

x

is large, the

x

2

terms will dominate the values of the numerator and denominator, making both positive.

Hence the sign of the value of the rational expression in each of the intervals

(

−

∞

,

−

3

)

,

(

−

3

,

−

1

)

,

(

−

1

,

2

)

,

(

2

,

4

)

and

(

4

,

∞

)

follows the pattern

+

−

+

−

+

. Hence the intervals

(

−

3

,

−

1

)

and

(

2

,

4

)

are both part of the solution set.

When

x

=

−

1

or

x

=

4

, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).

When

x

=

−

3

or

x

=

2

, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.

Hence the solution is:

x

∈

[

−

3

,

−

1

)

∪

[

2

,

4

)

graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}

8 0
3 years ago
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