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AnnZ [28]
2 years ago
12

16. For any two integers a and b, (a + b)2 = a² + b2 true or false

Mathematics
2 answers:
sukhopar [10]2 years ago
8 0
<h3>The statement is false.</h3>

Solution:

  • (a+b)^2
  • = (a+b)(a+b)
  • = a^2 + ab + ab + b^2
  • = a^2 + 2ab + b^2

So the statement is false and the correct statement is:

For any two integers a and b, (a+b)^2 = a^2+2ab+b^2.

il63 [147K]2 years ago
6 0

Answer:

false is the answer ........

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Someone explain this to me
e-lub [12.9K]

Answer: a) y = f(x - 6)

              b) y = f(x) - 2

<u>Step-by-step explanation:</u>

For transformations we use the following formula: y = a f(x - h) + k

  • a = vertical stretch
  • h = horizontal shift (positive = right, negative = left)
  • k = vertical stretch (positive = up, negative = down)

a) f(x) has a vertex at (-1, 1)

    M has a vertex at (5, 1)

    The vertex shifted 6 units to the right  → h = +6

Input h = +6 into the equation and disregard "a" and "k" since those didn't change.     ⇒ y = f(x - 6)

b) f(x) has a vertex at (-1, 1)

    N has a vertex at (-1, -1)

    The vertex shifted down 2 units  → k = -2

Input k = -2 into the equation and disregard "a" and "h" since those didn't change.     ⇒ y = f(x) - 2

7 0
3 years ago
How do I dilate this figure while k=5/2?
velikii [3]
Search I think google have the have answer most of time
7 0
3 years ago
Please help me with both one and two. Thanks!!
lesya [120]
1. a²+b²=c²
a=6²=36
b=x²
c=15²=225
x=√189 feet deep (the square root of 189)
2. a²+b²=c²
a=3²=9
b=x²
c=5²=25
x=√16=4

Hope that helped
;)
3 0
3 years ago
There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther
grigory [225]

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

\frac{2}{n}=\frac{3}{d}...(1) or

n=\frac{2d}{3}...(1)

For every 2 dimes there are 5 quarters. We can represent this information in an equation as:

\frac{2}{d}=\frac{5}{q}...(2) or  

q=\frac{5d}{2}...(2)  

There are 500 coins total. We can represent this information in an equation as:

n+d+q=500...(3)

We will use substitution method to solve our given system.

Upon substituting equation (1) and equation (2) in equation (3), we will get:

\frac{2d}{3}+d+\frac{5d}{2}=500  

Multiply the equation by 6:

\frac{2d}{3}*6+d*6+\frac{5d}{2}*6=500*6  

2d*2+6d+5d*3=3000  

4d+6d+15d=3000  

25d=3000  

\frac{25d}{25}=\frac{3000}{25}  

d=120  

Therefore, there are 120 dimes in the piggy bank.

Upon substituting d=120 in equation (1), we will get:

n=\frac{2(120)}{3}

n=2(40)

n=80

Therefore, there are 80 nickels in the piggy bank.

Upon substituting d=120 in equation (2), we will get:

q=\frac{5d}{2}  

q=\frac{5(120)}{2}  

q=5(60)  

q=300  

Therefore, there are 300 quarters in the piggy bank.

Now, we need to find the value of all coins.

We know 1 quarter is worth $0.25, so 300 quarters will be worth \$0.25\times 300=\$75.

We know 1 dime is worth $0.10, so 120 dimes will be worth \$0.10\times 120=\$12.

We know 1 nickel is worth $0.05, so 80 nickels will be worth \$0.05\times 80=\$4.

\text{All coins worth}=\$75+\$12+\$4

\text{All coins worth}=\$91

Therefore, all coins in the piggy bank worth $91.

7 0
3 years ago
What is the measure of y?
Ilya [14]

Answer:

=8

Step-by-step explanation:

=4, =16 =?

16-4=8⇚

=8

6 0
2 years ago
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