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AnnZ [28]
3 years ago
12

16. For any two integers a and b, (a + b)2 = a² + b2 true or false

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0
<h3>The statement is false.</h3>

Solution:

  • (a+b)^2
  • = (a+b)(a+b)
  • = a^2 + ab + ab + b^2
  • = a^2 + 2ab + b^2

So the statement is false and the correct statement is:

For any two integers a and b, (a+b)^2 = a^2+2ab+b^2.

il63 [147K]3 years ago
6 0

Answer:

false is the answer ........

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Victoria buys two pair of sunglasses for $8 each. About how much did she pay for both pairs of glasses? Round to the nearest ten
kumpel [21]

Victoria buys 2 pairs of sunglasses for $8 each

1 pair of glasses = $8

8 x 2 = total amount

multiply

8 x 2 = 16

total amount = 16

She payed $16 for both pairs of glasses.

hope this helps

7 0
3 years ago
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7,000lbs times what would equal 3.5 tons
PSYCHO15rus [73]
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3 years ago
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
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Suppose the temperature outside is dropping 3 degrees each hour how much will the temperature drop in 8 hours
vovikov84 [41]
It would drop by 24 degrees

3 x 8 = 24

For each hour another long way is simple just do

3 x 4 = 12 now just double it
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3 years ago
I have a question in math, will give brainliest
iris [78.8K]

Answer:

2^3

Steps if you need

Multiple

Square root

Next number

Reduce

4 0
3 years ago
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