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2 years ago

16. For any two integers a and b, (a + b)2 = a² + b2 true or false

Mathematics

2 answers:

sukhopar [10]2 years ago

8 0

<h3>The statement is false.</h3>

Solution:

(a+b)^2
= (a+b)(a+b)
= a^2 + ab + ab + b^2
= a^2 + 2ab + b^2

So the statement is false and the correct statement is:

For any two integers a and b, (a+b)^2 = a^2+2ab+b^2.

il63 [147K]2 years ago

6 0

Answer:

false is the answer ........

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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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2 years ago

Blopie help me :(((((

12345 [234]

Step-by-step explanation:

first you have to see the triangle BCD

then hypotheses and perpendicular are given so you have to find base

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2 years ago

A customer buys 17.01 in gas and request one five dollar lottery ticket two one dollar lottery tickets and one three lottery tic

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The store clerk gave the customer:

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$3 ticket . . . . . . 3
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The customer gave the store clerk:

$5 ticket . . . 5
$2 ticket . . . 2
cash. . . . . 100

Total. . . . $107

The store clerk owes the customer ($107 - $27.01) = $ 79.99 .

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2 years ago

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Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee

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To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
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</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>

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2 years ago

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The Weston Laundry washes all the linens for local hotels. In 7 days, they washed 285.38 pounds of towels and 353.47 pounds of s

Serhud [2]

In the problem it is already given that Weston Laundry washed 285.38 pounds of towel and 353.47 pounds of sheets from local hotels in 1 day. Firstly we have to find the total pounds of linens that Weston Laundry has washed in 7 days. Then only will it be possible to find the amount of linen washed in a day.
Then t
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Then
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So Weston Laundry washed about 91.26 pounds of linen each day.

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