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lbvjy [14]
3 years ago
11

What is the slope of the line shown in the graph? ​

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

-2 = 2 units down and +1 = 1 unit to the right. -2/1

Step-by-step explanation:

You might be interested in
Which of the following could be the graph of 3x + 4y = 12?​
Elan Coil [88]

Answer:

A graph that goes through (4, 0), (8, -3), (0, 3), and (-4, 6)

Step-by-step explanation:

Hello!

To find what this looks like it is easier to put it into slope-intercept form which is y = mx + b

To get our equation to look like that we have to get y by itself

3x + 4y = 12

Subtract 3x from both sides

4y = -3x + 12

Divide both sides by 4

y =- \frac{3}{4}x  + 3

We now know the y-intercept is (0, 3)

Now we follow the slope to give us more points

More points are (4, 0), (8, -3), and (-4, 6)

The answer would be a graph that goes through those points.

Hope this helps!

6 0
3 years ago
What would be the awnsers
Fittoniya [83]
The answer would be 42
8 0
3 years ago
What is 481 squared in expanded form?
netineya [11]

481*481= 231361

That in expanded form is

200000 + 30000 + 1000 + 300 + 60 + 1

Sorry if i am wrong I truely am

7 0
4 years ago
The number of gift baskets Penelope can make varies directly with the amount of time she spends making the baskets.
insens350 [35]
She can make 40 baskets in 5 hours because in 1 hour she can make 8 so 8 times 5 is 40
3 0
3 years ago
Read 2 more answers
We are interested in the amount that students study per week. Suppose you collected the following data in hours {4.4, 5.2, 6.4,
olga nikolaevna [1]

Answer:

Step-by-step explanation:

Hello!

The objective is to estimate the average time a student studies per week.

A sample of 8 students was taken and the time they spent studying in one week was recorded.

4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4

n= 8

X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74

S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94

S= 1.39

Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2}* (S/√n)

t_{n-1;1-\alpha /2}= t_{7;0.975}= 2.365

6.74 ± 2.365 * (1.36/√8)

[5.6;7.88]

Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]

I hope this helps!

3 0
4 years ago
Read 2 more answers
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