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Mrac [35]
2 years ago
13

NEED HELP ASAP. ONLY ANSWER IF YOU CAN EXPLAIN THIS CORRECTLY

Mathematics
1 answer:
ss7ja [257]2 years ago
4 0

Answer:

B. f(x) and g(x) have a common x-intercept.

Step-by-step explanation:

When x = 2 for g(x), the output is 0.

When x = 2 for f(x), the output is also 0.

So, that would mean that f(x) and g(x) have a common x-intercept.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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VladimirAG [237]
129 hundreths. Hope this helps.
4 0
3 years ago
Read 2 more answers
Use compatible numbers to solve the problem 488 ÷ 62.A. 450 ÷ 50 = 9B. 434 ÷ 62 = 7C. 490 ÷ 70 = 7D. 480 ÷ 60 = 8
ipn [44]

Option D is correct. The required compatible number is 480 ÷ 60 = 8

Compatible numbers are numbers that have a close approximate to a given value

Given the expression  488 ÷ 62

The compatible number for 488 is 480

The compatible number for 62 is 60

Using these compatible numbers to solve the expression will give:

488 ÷ 62

= 480 ÷ 60

= 480/60

= 48/6

= 8

Hence the correct option will be 480 ÷ 60 = 8

Learn more here: brainly.com/question/22595072

8 0
3 years ago
Can someone please tell me the answer to this?
Neko [114]
A) 3b-7b
-4b

b) a+a-5a
-3a

c) -3-3r
cannot be simplified, no like terms

d) 7t-8t-8
-t-8

e) -15p-20
cannot be simplified, no like terms

f) -g-g-g
-3g
5 0
3 years ago
In an experiment to determine whether there is a systematic difference between the weights obtained with two different mass bala
Maslowich

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

<u>6                     12.74      12.75          -0.01        0.001</u>

<u>∑                                                      0.06         0.0173</u>

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

3 0
3 years ago
Please answer ! will give brainliest
kotegsom [21]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
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