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Mkey [24]
3 years ago
15

A middle school took all of its 6th grade students on a field trip to see a ballet at a theater that has 2900 seats. The student

s filled 986 of the seats in the theater. What percentage of the seats in the theater were filled by the 6th graders on the trip?
Mathematics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

34%

Step-by-step explanation:

986/2900  x 100 = 34%

lesantik [10]3 years ago
5 0

Answer:

34%

Step-by-step explanation:

To find what percent a part is of the whole, divide the part by the whole and multiply by 100%.

\dfrac{986}{2900} \times 100\% = 0.34 \times 100\% = 34\%

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G and H are mutually exclusive events.<br> • P(G) = 0.5<br> • P(H) = 0.3<br> Find<br> P(H OR G).
Sedaia [141]

Answer:

0.8

Step-by-step explanation:

Mutually exclusive:

P(G U H) = P(G) + P(H)

Because no intersection

P(G U H) = 0.5 + 0.3 = 0.8

6 0
3 years ago
Angle Addition Crossword
Elena-2011 [213]

Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

                  = 21° + 37°

                  = 58°

2). m∠BED = m∠BEC + m∠CED

                   = 37° + 44°

                   = 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

                = m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

                = 2∠IKH + m∠HKG

         103° = 2∠IKH + 41°

   2(∠IKH) = 103 - 41

 m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

                  = 21° + 37° + 44°

                  = 102°

5). m∠JKG = 108°

    m∠JKG = m∠JKI + m∠IKH + m∠HKG

    108° = m∠JKI + 31° + 41°

    m∠JKI = 108° - 72°

    m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

                  = m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

                  = 31° + 41°

                  = 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

                 = 36° + 103°

                  = 139°

8). m∠MQO = 2(m∠NQO)

                    = 2(64)°

                    = 128°

9). m∠LQO = 156°

    m∠LQM = m∠LQO - m∠MQO

                    = 156° - 128°

                    = 28°

10. m∠NQP = m∠NQO + m∠OQP

                   = 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

                   = 64° + 28°

                   = 92°

5 0
3 years ago
Draw two segments. How many common points is it possible for the segments to have? Explore all possibilities.
Arte-miy333 [17]

A segment is bounded by two endpoints.

The two segments can have up to two common points

Assume the line segments are AB and CD where the length of AB is greater than the length of CD.

<u>The possibilities are:</u>

  • <em>A point of segment CD lies on segment AB</em>
  • <em>Both points of segment CD lie on segment AB.</em>

<em />

See attachment for both possibilities.

Hence, it is possible for the two segments to have two common points.

Read more about line segments at:

brainly.com/question/18983323

7 0
3 years ago
Choose the graph below that correctly represents the equation 3x + 9y = −18. (5 points)
Tju [1.3M]

Answer:

the line through the points negative 6 comma 0 and 0 comma negative 2

Step-by-step explanation:

Rewrite the equation to something you are familiar with such as the slope intercept form; y = mx + b. This means you need to solve for y.

3x + 9y = -18 --- divide everything by 3.

x + 3y = -6

3y = -6 - x

y = -2 - 1/3x

your slope is -1/3 and your y intercept is - 2.

remember, y-intercept is when x = 0. therefore, when x = 0, y = -2.

write as an ordered pair (0, -2). the only option that has (0, -2) is the second one.

Therefore, the line through the points negative 6 comma 0 and 0 comma negative 2.

5 0
3 years ago
Given x and y are integers, explain why the product of the expression and it's conjunct will always be an integer
mars1129 [50]

Answer:

If neither of the two real numbers is zero, then their product is also not zero Suppose also that x is a real number that satisfies the equation The " / " symbol does not always give you a result of an integer, so be careful.pkek, and any other expression for n as a product of prime numbers is identical to this except,.

Step-by-step explanation:

4 0
3 years ago
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