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Ipatiy [6.2K]
3 years ago
12

Herbert was given a pocket watch bass grandfather. The value of the watch, for any given year, t, from the time Herbert received

it is modeled by the function f(t) = 150(1.35)^t. He was also given a classic guitar. It's value for any given year is modeled by the function represents in the table:
t: 0, 1, 2, 3, 4
g(t): 175 210, 252, 302.40, 362.88
What is the positive difference in values of the items in the sixth year?
A.) $385.57
B.) $472.66
C.) $835.54
D.) 893.60
Mathematics
1 answer:
Archy [21]3 years ago
4 0

The Answer:

A or 385.57

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Factor x^5+4x^4−7x^3−34x^2−24x
zloy xaker [14]
This is your perfect answer

7 0
3 years ago
Can someone please help me? Please C: And thanks!
elixir [45]

Answer:

$540.98

Step-by-step explanation:

future value= $ 50,000

number of deposits (n)= 8*12 = 96

rate (r) = 4% per month

= 4÷12 per annum

= 0.33% p.a

i = 0.33÷100

= 0.0033

We know,

Future value of annuity = P÷i [ (1 + i)^n - 1 ]

$50,000 = P÷ 0.0033 [ ( 1+0.0033)^96 - 1]

$50,000 * 0.0033=P [ (1.0033)^96 - 1 ]

$165 = P*0.305

P = $165÷0.305

P = $ 540.98

Rough::

let x= 1.0033)^96

log x = 96 * log (1.0033)

log x = 0.1156

x = Antilog (0.1156)

= 1.305

1.305 - 1 = 0.305

6 0
3 years ago
Help please please please please please<br> 6th &amp; 7th
raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. log_a_ba=\frac{1}{3}

The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
so x= 2 or -2

Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

the four real solutions are 2, -2, \sqrt{2} ,-\sqrt{2}



6 0
3 years ago
Find the missing fraction.<br> 3<br> 2<br> 3
katovenus [111]
The missing fraction is -1/12
5 0
3 years ago
This is the question ​
aivan3 [116]

Answer:

use desmos irs a graphing caculator it helped me gat all my answear with inequality

4 0
3 years ago
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