Answer:
x = ± 
Step-by-step explanation:
-8 - 8x^2= -31
Since this is a quadratic, it needs to be factored.
First, move the x to the other side:
-8 = 8x^2 - 31
Then, get the x alone by first adding 31:
23 = 8x^2
then dividing by 8:
x^2 = 23/8
Finally, square root both sides and remember the even roots property:
x = ± 
and simplify the root 8:
x = ± 
Note: This answer may have a mistake.
Answer:
Option 3 3 1/8x - 6 3/10
Step-by-step explanation:
(3 1/2x - 4 1/10) - (3/8x + 2 1/5)
Divide it into parts:
(3 1/2x - 3/8x) + (-4 1/10 - 2 1/5)
3 1/2x - 3/8x = 3 4/8x - 3/8x = 3 1/8x
-4 1/10 - 2 1/5 = -4 1/10 - 2 2/10 = -6 3/10
So we get:
2 1/4x - 6 3/10
True
4x^2 -16x +16 = (2x -4)^2
A = 2x
B = 4
645 feet.
Explanation:
We know that are 3 feet in a yard, so let's set up a proportion to solve this
x215
3 feet n
-------- = -----------
1 yard 215 yards
x 215
We are solving for n. To get from 1 to 215, we multiply by 215. So to get from 3 to the answer, we must multiply by 215 as well. 3 x 215 = 645, therefore that is the answer.
Answer:
A. H(x) is an inverse of F(x)
Step-by-step explanation:
The given functions are:



We compose F(x) and G(x) to get:






Hence G(x) is not an inverse of F(x).
We now compose H(x) and G(x).



We simplify to get:


Since
, H(x) is an inverse of F(x)