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3 years ago

Make a the subject of the formula where a is positive: a 6(a - 4b) = 2ac + 4d

Mathematics

1 answer:

ivolga24 [154]3 years ago

8 0

Answer:

${ \tt{6(a - 4b) = 2ac + 4d}} \\ \\ { \tt{6a - 24b = 2ac + 4d}} \\ \\ { \tt{6a - 2ac = 4d + 24b}} \\ \\ { \tt{a(6 - 2c) = 4d + 24b}} \\ \\ { \boxed{ \tt{ \: a = \frac{4d + 24b}{6 - 2c} }}} \\$

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Please help me

Alla [95]

Answer:

Step-by-step explanation:

Let one number = x

Let the other number = y

x + y = 9

xy2 is a maximum

Since we need positive numbers, we assign values of x and y respectively that will give us a sum of 9.

x: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

y: 9, 8, 7, 6, 5, 4, 3, 2, 1, 0

Next, we square the values of y.

y2: 81, 64, 49, 36, 25, 16, 9, 4, 1, 0

Next, we multiply x by y2 to see which product is the highest value.

x : 0 , 1 , 2 , 3 , 4 , 5 , 6, 7, 8, 9

y2 : 81, 64, 49, 36, 25, 16, 9, 4, 1, 0

We can eliminate x = 0, x = 8 , and x = 9 , since the product of xy2 is of lowest value.

1 x 64 = 64

2 x 49 = 92

3 x 36 = 108

4 x 25 = 100

5 x 16 = 80

6 x 9 = 54

7 x 4 = 28

The highest product value here is 108.

The two numbers in the solution are 3 and 6.

7 0

3 years ago

Find the area of this shape.

mart [117]

Answer:

shape AREA= 35cm^2

Step-by-step explanation:

you should know that this shape is a combination of triangle and trapezoid. therefore you have to find the area of each shape and add them.

A=h/2(b1 + b2) for trapezoid

A=2/2((4+4)+4)

A=1*12

A=12cm^2

A=bh/2. for TRIANGLE

A=1/2((4+4)*5.75)

A=1/2(46)

A=23cm^2

shape AREA= triangle AREA + trapezoid AREA

shape AREA=12cm^2 + 23cm^2

shape AREA= 35cm^2

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4 years ago

Over 12 months, the value of Mrs. Marino's stocks dropped

adelina 88 [10]

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3 years ago

Someone plz help me lol

riadik2000 [5.3K]

Answer:

the correct anwser is b b cause they both are positive y intercepts

7 0

3 years ago

24 , Factor: x²-9 A (x + 3XX-3) B (x+3)2 с (x-3) (x+3)(x+3)

Katarina [22]

Answer:

(x-3)(x+3)

Step-by-step explanation:

We are given the expression $\displaystyle \large{x^2-9}$ :—

To factor this expression, we have a formula for it which is difference of two squares:—

$\displaystyle \large{a^2-b^2=(a+b)(a-b)}$

You can also swap from $\displaystyle \large{(a+b)(a-b)}$ to $\displaystyle \large{(a-b)(a+b)}$ via multiplication property.

From the expression, factor using the formula above:—

$\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}$

Therefore, the factored expression is:—

$\displaystyle \large{\boxed{(x-3)(x+3)}}$

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If you have any questions regarding the problem or need clarification of my answer/explanation, do not hesitate to ask in comment!

5 0

2 years ago

Make a the subject of the formula where a is positive: a 6(a - 4b) = 2ac + 4d ​

Make a the subject of the formula where a is positive: a 6(a - 4b) = 2ac + 4d