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3 years ago

What are 4 molecules made of the same substance

Chemistry

2 answers:

slavikrds [6]3 years ago

6 0

Answer:

<h3>H2O (water)</h3><h3>N2 (nitrogen)</h3><h3>O3 (ozone)</h3><h3>CaO (calcium oxide)</h3><h3>Explanation:</h3>

<u>H</u><u>OPE </u><u>IT</u><u> HELPS</u>

Travka [436]3 years ago

3 0

<h3>What molecules are in a substance?</h3>

molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.What are 4 examples of molecules?

<h3>Here are examples of common molecules:</h3>

•H2O (water)

•N2 (nitrogen)

•O3 (ozone)

•CaO (calcium oxide)

•C6H12O6 (glucose, a type of sugar)

•NaCl (table salt)

<h3>In chemistry, isomers are molecules or polyatomic ions with identical molecular formulas — that is, same number of atoms of each element — but distinct arrangements of atoms in space. ... Two molecules that are the same stereoisomer as each other might be in different conformational forms or be different isotopologues.</h3>

Explanation:

(ﾉ◕ヮ◕)ﾉ*.✧

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??????????????????<br> Why are quantities important in the study of chemistry give an example please

slamgirl [31]

Answer:

Chemistry is the study of matter and how it behaves.

The scientific method is the general process by which we learn about the natural universe.

Explanation:

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3 years ago

Given: 2H2O2 → 2H2O + O2 structure of H2O2: H–O–O–H Bond Bond Energy (kJ/mol) O–H 459 O=O 494 O–O 142 Based on the given bond en

ICE Princess25 [194]

Answer:

B. - 210 kJ

Explanation:

<em>∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.</em>

The bond formation in the products releases energy (exothermic).

The bond breaking in the reactants requires energy (endothermic).

The products:

H₂O contains 2 O-H (- 459 kJ/mol) bonds.

O₂ contain 1 O=O (- 494 kJ/mol) bond.

The reactants:

H₂O₂ contain 2 O–H (459 kJ/mol) bonds and 1 O–O (142 kJ/mol) bond.

∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.

<em>∴ ΔHrxn = [2 (2 x (O–H bond energy) + (1 x (O=O bond energy)] - 2 [(2 x (O–H bond energy) + (1 x (O–O bond energy)] </em>= [2 (2 x - 459 kJ/mol) + (1 x - 494 kJ/mol)] - 2 [(2 x 459 kJ/mol) + (1 x 142 kJ/mol)] = (- 2330 kJ) + (2120 kJ) = <em>- 210 kJ.</em>

5 0

3 years ago

What safety precautions must be observed with hydrochloric acid? with silver nitrate?

skad [1K]

Hydrochloric acid is very corrosive. Handling it should be properly taken cared off. Personal protective equipment should be worn at all times when using this substance. PPE includes gloves specific for the substance used, goggles, closed flat shoes and laboratory gown. The same should be done for handling silver nitrate.<span />

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3 years ago

Can you help me on this

lapo4ka [179]

A football field is 0.001 km in length. Since the 1 is in the thousands place, you’d have to run back and forth (0.001 km) 1000 times.

0.001 x 1000 = 1

6 0

4 years ago

Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 32.4 g of carbon and 37

Gnoma [55]

Answer:

The answer to your question is:

Explanation:

Law of constant composition states that a given compound always contains its component elements in a fixed ratio.

Data

Sample 1 32.4 g of C and 373 g of Cl

Sample 2 12.3 g of C and 112 g of Cl

Convert the grams to moles and compare the ratios

Sample 1 Sample 2

12 g of C --------------- 1 mol 12 g of C -------------- 1 mol

32.4 g ---------------- x 12.3 ------------- x

x = (32.4 x 1) / 12 x = (12.3 x 1) / 12

x = 2.7 moles of C x = 1.025 moles of C

35.5 g of Cl ---------- 1 mol 35.5 g of Cl ---------- 1 mol

373 g ------------------ x 112 g of Cl ----------- x

x = (373 x 1) / 35.5 x = (112 x 1) / 35.5

x = 10.5 moles of Cl x = 3.15 moles of Cl

Ratio

10.5 / 2.7 = 3.9 3.15/1.025 = 3.1

The ratio must be equal in both samples to say that the law is constant. So the answer is NO.

2.-

1) H3PO4 3 hydrogens

2) Na2HPO4 1 hydrogen

3) Ca(HCO3)2 2 hydrogens

4) Ba(C2H3O2)2 6 hydrogens

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3 years ago