The reaction of sugar with oxygen is as follows:
C₁₂H₂₂O₁₁ + 12 O₂ → 12 CO₂ + 11 H₂O
When in the presence of pure oxygen, sucrose (table sugar) will not form caramel, in fact it will combust into carbon dioxide and water like any other carbohydrate.
Caramel is actually formed by slowly heating sucrose to high temperatures of around 170 °C resulting in thermal decomposition. This essentially removes molecules of water from the sucrose which results in the compound isomerizing and eventually polymerizing to form caramel. The chemical make up of caramel is the same as sucrose, so it will still be composed of carbon, hydrogen and oxygen.
1 milliliter of water (ml)
Equals : 0.04 ounces of water (oz wt.)
Fraction : 1/25 ounces of water (oz wt.)
Answer:
See explanation
Explanation:
If we look at the structure of X, we will discover that X is an organic compound. The compound will certainly have a much lower melting point than sand.
This is because, sand is composed of high melting point inorganic materials.
Hence, even though the researcher accidentally spilled some sand into the the beaker containing the crystalline substance X, he does not need to be perturbed since the melting point of X is much lower than that of sand
it is important to check the conductivity and pH of pure water to:
1- to check the purity of water and if it healthy or not , and the water source.
2- we have to measure the PH to know the alkalinity or acidity of water. If the PH > 7 so it is acidic , if PH < 7 so it is alkaline.
3- we have to measure the conductivity of the water as it is an indication for the impurity level. and it shouldn't be high to keep the water healthy.
