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Vladimir79 [104]
3 years ago
14

Determine the number of seconds there are in 30 hours

Chemistry
2 answers:
jeka943 years ago
8 0

Answer:

108000 seconds

Explanation:

60 seconds in a minute. 60 minutes in an hour. 60 × 60 is 3600. 3600 × 30 is 108000

8_murik_8 [283]3 years ago
8 0

Answer:108,000

Explanation:

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What energy is used when you ring a church bell?
nadezda [96]
Kinetic energy :) :)
3 0
3 years ago
What is the pH of a solution prepared by mixing 100.00 mL of 0.020 M Ca(OH)2 with 50.00 mL of 0.100 M NaOH? Assume that the volu
klemol [59]

Answer:

The pH of the solution is 12.78.

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution. The pOH is defined as the negative logarithm of the activity of the hydroxide ions. That is, the concentration of OH- ions:

pOH= - log [OH-]

On the other side, Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume. Molarity is calculated as:

Molarity= \frac{number of moles}{volume}

Molarity is expressed in units: \frac{moles}{liter}

In this case, the solution is prepared by mixing 100 ml (equal to 0.1 L, where 1000 mL = 1 L) of Ca(OH)₂ 0.020 M with 50 ml (equal to 0.05 L) of 0.100 M NaOH. Then, Ca(OH)₂ and NaOH are strong bases, so they dissociate completely. In the case of the first hydroxide, for each mole of Ca(OH)₂,

form two moles of OH-. In the case of sodium hydroxide, for each mole of hydroxide, one mole of OH- is formed. So, taking into account the definition of molarity, the number of moles of OH- that each hydroxide contributes to the solution is calculated as:

From Ca(OH)₂: 0.1 L* 0.02 M*2 = 0.004 moles

From NaOH: 0.05 L* 0.1 M= 0.005 moles

So, the amount of total moles of OH- is the sum that each hydroxide contributes to the solution: 0.004 moles + 0.005 moles= 0.009 moles

On the other hand, volumes are additive. Then: 0.1 L +  0.05 L= 0.15 L

Replacing in the definition of molarity the number of moles and the volume:

[OH-]=\frac{0.009 moles}{0.15 L}

Solving:

[OH-]= 0.06 \frac{moles}{liter}

Replacing in the definition of pOH:

pOH= - log 0.06

pOH= 1.22

The following relationship can be established between pH and pOH:

pH + pOH= 14

Being pOH= 1.22 and replacing:

pH + 1.22= 14

pH= 14 - 1.22

pH= 12.78

<u><em>The pH of the solution is 12.78.</em></u>

7 0
3 years ago
What volume of gold would be equal in mass to a piece of copper with a volume of 141 ml? the density of gold is 19.3 g/ml; the d
sergejj [24]
We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Details:

Density of Copper= 8.96 g/ml
Volume of Copper=141 ml
mass of Gold = mass of Copper
Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula
Density= mass/volume

Since we are to solve for the mass of copper
mass of copper= Density of Copper * Volume of Copper
mass of copper= 8.96 g/ml* 141 ml= 1263.36 g
Thus,
mass of gold=mass of copper=1263.36 g
Hence,
Using still the density formula to solve for the volume of gold,
Volume of gold=mass of gold/ Density of gold
Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper
8 0
3 years ago
A match has about 21 milligrams of red phosphorus coating the tip. How many atoms of phosphorus is this?
MAXImum [283]

Answer:

4.083 * 10^20 atoms.

Explanation:

One Mole of phosphorus  contains 6.022 * 10^23 atoms (Avogadros number)'

Since 1 mole of Phosphorus  has a mass of  30.974 grams, 21 milligrams has

6.022 * 10^23  * 0.021 / 30.974

= 0.004083 * 10^23

= 4.083 * 10^20

3 0
3 years ago
PLEASE HELP!!!!!!!!!
KonstantinChe [14]

Answer:

Option "C" is the correct answer to the following question.

Explanation:

Given:

Pressure in an automobile tire (P) = 1.88 atm

Temperature (K) = 25°C = 273 + 25 = 298 Kelvin

New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin

Find:

New pressure in an automobile tire (P1) = ?

Computation:

\frac{P}{K}= \frac{P1}{K1} \\\\\frac{1.88}{298}= \frac{P1}{310}\\\\1.9557

New pressure in an automobile tire (P1) = 1.9557

New pressure in an automobile tire (P1) = 1.96 (Approx)

5 0
3 years ago
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