We would need a sample size of 560.
We first calculate the z-score associated. with this level of confidence:
Convert 95% to a decimal: 95% = 95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975
Using a z-table (http://www.z-table.com) we see that this is associated with a z-score of 1.96.
The margin of error, ME, is given by:

We want ME to be 4%; 4% = 4/100 = 0.04. Substituting this into our equation, as well as our proportion and z-score,
Answer:
129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.
Answer:
Step-by-step explanation:
If you graph there would be two different regions. The first one would be

And the second one would be
.
If you rotate the first region around the "y" axis you get that

And if you rotate the second region around the "y" axis you get that

And the sum would be 2.51+4.188 = 6.698
If you revolve just the outer curve you get
If you rotate the first region around the x axis you get that

And if you rotate the second region around the x axis you get that

And the sum would be 1.5708+1.0472 = 2.618
Answer:
Hello,
Step-by-step explanation:
Best fit: quadratic y=5.3x²-9.3+6.1
with an total error of 0.4
Buzz has 4 friends and Brock has 6.
The reason being is that Buzz has to have two less friend than Brock has, and yet still both have to add up to ten.