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Degger [83]
3 years ago
10

What is the difference between alkali metals and halogens?

Chemistry
2 answers:
Airida [17]3 years ago
4 0
<h3>→soft and reactive metals. </h3>

Explanation:

<h3>Alkali metals are soft and reactive metals. They react vigorously with water and become more reactive. And other hand halogens are reactive non metals. ... Halogens can be solid, liquid, gaseous at room temperature and the melting point increase when they get bigger.</h3>

<h2>#CAREYINGTOLEARN❤️</h2>
alexandr1967 [171]3 years ago
4 0

Explanation:

alkalin metals is the first group in the periodic table

halogen is the 7 group in the periodic table

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Which compound has the lowest pka? (ch3ch2o2c)2ch2 ch3ch2o2cch2cho ch3ch2coch2cho phcoch2coch3 (nc)2ch2?
nexus9112 [7]

Aldehydes having the lowest pKa value around 17 and thus the other carbonyl have higher pKa than aldehyde.

Now, two aldehyde are present in given sereis such as

ch3ch2o2cch2cho and ch3ch2coch2cho

ch3ch2coch2cho is more acidic or having low pKa than ch3ch2o2cch2cho due to the presence of carbonyl at alpha position of aldehyde and rasonance will take place in ch3ch2coch2cho which result in release of proton readilly.

Hence, ch3ch2coch2cho having low pKa value of all and thus is highly acidic of all.

6 0
4 years ago
Nitrogen makes up what percentage of the mass of the human body
galina1969 [7]
I think it's 3 % of the body.

3 0
3 years ago
Read 2 more answers
PLEASE HELP ANYONE IM TOO DUMB TO ANSWER THESE :(
AlladinOne [14]

Answer:

The "2" applies only to the sodium, and sugar is a substance

Explanation:

The amount of atoms in an element are written using small letters after the element they refer to.

3 0
4 years ago
2 Students were asked to identify the location of elements in the periodic table based on clues
rjkz [21]

Answer:

B

Explanation:

I took the test

3 0
3 years ago
Given:
marusya05 [52]

Answer:

92.6 g.

Explanation:

  • The balanced equation is:

CaC₂ + N₂ → CaCN₂ + C.

  • It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
  • We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:

n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.

  • We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.

∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.

<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>

  • Now, we can get the grams of N₂  consumed to produce 265.0 g of CaCN₂:

∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.

7 0
4 years ago
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