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Degger [83]
2 years ago
10

What is the difference between alkali metals and halogens?

Chemistry
2 answers:
Airida [17]2 years ago
4 0
<h3>→soft and reactive metals. </h3>

Explanation:

<h3>Alkali metals are soft and reactive metals. They react vigorously with water and become more reactive. And other hand halogens are reactive non metals. ... Halogens can be solid, liquid, gaseous at room temperature and the melting point increase when they get bigger.</h3>

<h2>#CAREYINGTOLEARN❤️</h2>
alexandr1967 [171]2 years ago
4 0

Explanation:

alkalin metals is the first group in the periodic table

halogen is the 7 group in the periodic table

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Which shows the rational expression written using the least common denominator?
Alexandra [31]

Answer:

The first one.

\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you.  The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x².  The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way.  Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }

And now you have both fractions on the same denominator, without having changed their value, just their looks

6 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
Element A has 15 protons. Determine the number of neutrons in its isotope with mass number 33.
bagirrra123 [75]
In an electrically neuteral atom, number of protons = number of electrons = atomic number.
Mass number = neutrons + protons/electrons/atomic number
Therefore,
neutrons = mass number - <span>protons/electrons/atomic number
Neutrons = 33 - 15 = 18

The answer is thus B. But this is the solution and explanation along with it as proof.</span>
6 0
3 years ago
What is the half-life of A? What will the pressure, initially 32.1 kPa, at
kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant = 3.56\times 10^{-7} s^{-1}

initial pressure is = 32.1 kPa

half life of A is calculated as

t_{1/2} = \frac{ln 2}{k}

t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}

t_{1/2} = = 1.956 \times 10^6 s

for calculating pressure we have follwing expression

ln p = ln P_o - kt

P =P_o e^{-kt}

a) P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa

b) P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa

5 0
3 years ago
5,6-dimethyl-2-heptyne <br><br> Due in 1 hr pls help me
mina [271]

Answer:

Please see the attached pictures.

Explanation:

☆ To ensure that each carbon has 4 bonds, fill the other bonds with Hs.

4 0
3 years ago
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