The hypothesis is the question you are trying to answer or the problem you need to figure out, it is kind of like a starting point
Answer:
The correct answer is the formation of pyruvate from glucose willl be energetically less favorable.
Explanation:
According to the question matunt yeast has a shorter glycolytic pathay catalysing a follwing reaction
Glyceraldehyde-3-phosphate+H2O+NAD+ = 3-phosphoglycerate
So in the mutatant the formation of 1,3- bisphosphoglycerate is not occurring.The glyceraldehyde-3-phosphate is directly converted into 3-phosphoglycerate.
As a result the substrate level phosphorylation step that deals with formation of 3-phosphoglycerate from 1,3 bisphosphoglycerate is not occurring.
From this point of view it can be said that less energy will be formed in the mutant during glycolysis than that of normal one.
So the formation of pyruvate from glucose will be energetically less favorable.
Answer:
A) The pollen grains will be pure red.
Explanation:
Plants have alternation of generations, this means that there are two different stages in their life-cycle: a sexual haploid (n) phase and an asexual diploid phase (2n). These phases occur in different individuals, so there is an haploid plant called gametophyte that carries gametes and after fecundation, it will rise a diploid sporophyte (asexual).
In seed plants, the sporophyte is the plant that we normally see, and the gametophyte is reduced into an organ of the sporophyte. The male gametophyte is the pollen that is produced in the sporangium in anthers (parts of sporophyte). When a pollen grain fecundes a female gametophyte (egg), it will produce a diploid embryo or new sporophyte.
Therefore, if the researcher exposes pollen to both stains, these grain will stain red, because red stain identifies gametophyte tissue.
