Answer:
Part A: Thr-Leu-Val
Part B: ACC-UUG-GUU
Explanation:
When you transcribe a DNA sequence to mRNA, you need to remember that in RNA there is no Thymine (T), instead it has Uracil (U). So the base pairings would be like this compared to DNA base pairing:
DNA RNA
A-T A-U
T-A T-A
C-G G-C
G-C C-G
Given the sequence the transcription will be as follows:
DNA : TGG - AAC - CAA
mRNA: ACC - UUG - GUU
Next, to translate it into amino acids, you will use the chart. Now amino acids pair in codons (3 base pairs at a time). Let's take the first codon in your sequence:
ACC
1st 2nd 3rd
A C C
Using the column on the left, find the row that matches it, so in this case A.
At the very top, there is another row of letters, looking at the row of A only, look for the column of the second base which is C.
Lastly, look at the right most column and find the letter that matches the third base within the box where A and C intersect. In this case, C is your third base.
The amino acid where all three intersect is your first amino acid which is Thr.
Just do this for the next codons and you will come up with the answer.
1 Met or Start (start codon)
2 Ala
Yes, that's a true statement.
Together, inhalation and exhalation are referred to as breathing. Inhalation is the process of breathing where air moves into the lungs through the nose and the mouth. This causes an increase in the volume of air in the lungs, meaning the pressure will decrease, thus the air then moves to the lungs. Exhalation on the other hand is the flow of the breath out of an organism, for example in humans it is the movement of air from the lungs out of the airways, to the external environment during breathing.
Although most absorbed glucose is used to make energy, some glucose is converted to ribose and deoxyribose, which are essential building blocks of important macromolecules, such as RNA, DNA, and ATP.
