Answer:
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median" is the "middle" value in the list of numbers
Step-by-step explanation:
hope it help
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
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Answer:
x = 28
Step-by-step explanation:
Let the total number of students = x
x/7 + 3x/7 + 2x/7 + 4 = x If that is all there is. If it isn't the problem can't be done. Combine like terms.
x(1 + 3 + 2)/7 + 4 = x
x (6/7) + 4 = x Subtract 6x/7 from both sides
4 = x - 6x/7
4 = 7x/7 - 6x/7 Combine
4 = 1/7x Multiply both sides by 7
4*7 = 7x / 7
x = 28
Answer:
Both of these equations are in slope-intercept form. The slope-intercept form of a linear equation is: y=mx+b
Where m is the y-intercept value.
y=-2x+5
y=-2x+20
The slope of the two equations are: m1=−2 and m2=−2
Step-by-step explanation:
Because the have the same slope it means the lines represented by these two equations are either parallel or are the same line.
The y-intercepts for the two lines are:b1 = 5 and b1=20