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3 years ago

Al used the expression

Mathematics

1 answer:

user100 [1]3 years ago

8 0

Following the order of operations, you first multiply 25 and 2.

Now you have 8+50-45

Then, you add and subtract left to right.

So, 58-45

58-45=13 CDs

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Which polynomial function has a root of 1 with multiplicity 2 and a root of 6 with multiplicity 1

Mashutka [201]

Answer:

$f(x)=x^3-8x^2+13x-6$

Step-by-step explanation:

We are given information about polynomial as

a root of 1 with multiplicity 2

so, one of factor is (x-1)^2

a root of 6 with multiplicity 1

so, another factor is (x-6)^2

so, we can write polynomial as

$f(x)=(x-1)^2(x-6)$

now, we can simplify it

$f(x)=(x-1)(x-1)(x-6)$

$f(x)=(x^2-2x+1)(x-6)$

So, we get polynomial as

$f(x)=x^3-8x^2+13x-6$

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