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valentina_108 [34]
3 years ago
15

Al used the expression

Mathematics
1 answer:
user100 [1]3 years ago
8 0

Following the order of operations, you first multiply 25 and 2.

Now you have 8+50-45

Then, you add and subtract left to right.

So, 58-45

58-45=13 CDs


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A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height
antiseptic1488 [7]
The height at t seconds after launch is
s(t) = - 16t² + V₀t
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Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
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16t² - 112t + 192 = 0
t² - 7t + 12 = 0
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t = 3 s, or t = 4 s

The projectile reaches a height of  192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
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t = 0 or t = 7 s

When t=0, the projectile is launched.
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Answer: 7 s

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3 years ago
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