Oof I was going to answer this but it got me confusion.
A. original stuff is for 6 ppl anf u need for 2. and since 2 is 3x less yhan six. divide the ingrefiants by 3.
b. for 15 ppl, 6 is default. dou le all ingtediants is for 12. thrn add 50% more. aka mulyiply all ingrediants by 2.5
Answer: 0.2872
Step-by-step explanation:
Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.
i.e. n= 1000 and x= 260
⇒ Sample proportion : ![\hat{p}=\dfrac{260}{1000}=0.26](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7B260%7D%7B1000%7D%3D0.26)
z-value for 95% confidence interval : ![z_c=1.960](https://tex.z-dn.net/?f=z_c%3D1.960)
Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-
![\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%2B%20z_c%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
![=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}](https://tex.z-dn.net/?f=%3D0.26%2B%20%281.96%29%5Csqrt%7B%5Cdfrac%7B0.26%281-0.26%29%7D%7B1000%7D%7D)
![=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872](https://tex.z-dn.net/?f=%3D0.26%2B%20%281.96%29%280.01387%29%3D0.26%2B0.0271852%3D0.2871852%5Capprox0.2872)
∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872
116/21 hope this helped !
Answer:
A - 4/13ths is a larger number
B- 3/10ths is a ratoinal mumner