Answer:
Net cost of the car lease Maggie has to pay at the end of lease is $.
Step-by-step explanation:
Given that,
2-years car lease cost per month is $597. Security amount which is refundable at the end of lease is $600. down payment and paid fees of lease made by her are $500 and $ 125.
To find:- Net cost of the lease to Maggie at the end of the lease?
From the question:-
Cost of lease per moth is $597.
security deposit amount is $600 (Refundable)
down payment made by her is $500.
and lease paid fees is $125.
Calculating the Net cost :-
Net cost = cost of lease for 2-years - down payment + security
deposit + lease paid fees
=
=
=
Here the net cost of lease for 2 years is $ 14553.
But the security amount is refundable So,
Final cost is = $
Hence,
Net cost of the lease Maggie has to pay at the end of lease is $.
I think the answer is
W=126
Answer:
round cake - 82.42 in^2
rectangular cake - 114 in^2
Round cake:
d = 7 in
r= d/2 = 7 in /2 = 3.5 in
h = 2
The surface area of a cylinder is: A = 2pie r^2 + 2pie rh The surface are of the round cake (cylindrical cake) excluding the bottom is
Area = 2pie r^2 + 2pie rh - pie r^2
Area = pie r^2 + 2pie rh
Area = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2
= 38.46 + 43.96
= 82.42 in^2
Rectangular cake:
w = 6 in |= 9 in h = 2 in
The surface area of a rectangle
A = 2wl + 2wh + 2lh
The surface are of the rectangular cake excluding the bottom is
A = 2wl + 2wh + 2lh - wl
A = wl + 2wh + 2lh
A = 6 * 9 + 2* 6 * 2 +2 *9 * 2
= 54 + 24 +36
= 114 in^2
Answer:
Step-by-step explanation:
In this problem we assume that
Segment PL, Segment AE and Segment RT are parallels
so
using proportion
we have
Remember that
substitute the values and solve for LE
Multiply in cross
1) The function is
3(x + 2)³ - 32) The
end behaviour is the
limits when x approaches +/- infinity.3) Since the polynomial is of
odd degree you can predict that
the ends head off in opposite direction. The limits confirm that.
4) The limit when x approaches negative infinity is negative infinity, then
the left end of the function heads off downward (toward - ∞).
5) The limit when x approaches positive infinity is positivie infinity, then
the right end of the function heads off upward (toward + ∞).
6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.
7)
x-intercepts ⇒ y = 0⇒ <span>
3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0
</span>
<span>⇒ (x + 2)³ = -1 ⇒ x + 2 = 1 ⇒
x = - 1</span>
8)
y-intercepts ⇒ x = 0y = <span>3(x + 2)³ - 3 =
3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 =
21</span><span>
</span><span>
</span><span>9)
Critical points ⇒ first derivative = 0</span><span>
</span><span>
</span><span>i) dy / dx = 9(x + 2)² = 0
</span><span>
</span><span>
</span><span>⇒ x + 2 = 0 ⇒
x = - 2</span><span>
</span><span>
</span><span>ii)
second derivative: to determine where x = - 2 is a local maximum, a local minimum, or an inflection point.
</span><span>
</span><span>
</span><span>
y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.</span><span>
</span><span>
</span><span>Then the function does not have local minimum nor maximum, but an
inflection point at x = -2.</span><span>
</span><span>
</span><span>Using all that information you can
graph the function, and I
attache the figure with the graph.
</span>