Up two over one so the slope is 2
R(t) = 4t
A(r) = π(r^2)
a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)
b) t = 4,
A(4) = 16*3.14*(16)^2 = 12,861.44
-2x + 5 = 1/3x - 22
-7/3x = -27
-7x = -81
x = 81/7 or 11.57
They will intersect when x = 81/7 or 11.57
Answer:
Shift 6 units right.
Step-by-step explanation:
Easiest way to answer this question is to plot the two graphs:
Let's plot these graphs and analyse each graph.
Lets take the graph of
that is attached.
We can clearly see that graph intersects x axis at x=0 and then essentially looks like y=x is mirrored by the y axis.
Now when we look at the
that is attached,
We can see that graph intersects x axis at x=6 and is a composite graph of
and its mirrored graph by y=6.
We can clearly see that graph has moved 6 units to the right.