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Fudgin [204]
3 years ago
7

At 30°c an almunium spher is 30cm³ long

Physics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

Change volume / volume = .5 / 30 = .01666

coefficient of volume expansion = 3 * 24E-6 = 72E-6

Change in temp = .0167 / 24E-6 = 232 deg C

Final temp = 232 + 30 = 262 deg C

Change in volume / volume = 3 * coeff linear expansion * change in deg C

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A spring whose spring constant is 270 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required
cricket20 [7]

Answer:

0.02585 BTU

Explanation:

Given: Spring constant, k = 270 lbf/in

Initial force, f =100 lbf

Compression, x = 1 in

Work done can be calculated as follows:

W = \int {(f+kx)} \, dx \\W = fx + \frac{1}{2}kx^2\\W= (100 lbf)(1 in)+ \frac{1}{2}(270 lbf/in)(1 in)^2\\W= 100+135 = 235 lbf in\\W=235 \times 0.00011 BTU = 0.02585 BTU

6 0
4 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work
goldenfox [79]

Answer:

Both

Explanation:

8 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!
konstantin123 [22]
.
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7 0
3 years ago
Read 2 more answers
A merry go round (mass of 200kg and radius 5m) is rotating so that the outside edge is moving 10m/s. A giant bug of 6kd at a dis
romanna [79]

Answer:

2 rad/s

Explanation:

For a rotating object, the linear velocity is given by

v=\omega r

where \omega is the angular velocity and r is the radius.

\omega=\dfrac{v}{r}

The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.

\omega=\dfrac{10 \text{ m/s}}{5 \text{ m}} = 2 \text{ rad/s}

8 0
4 years ago
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