Doe anyone get this

What is the difference between elastic force and gravitational force?

3241004551 [841]

There are four fundamental forces. Gravitational is one. Elastic is produced by Electrostatic Force( a different fundamental force!)
Gravity has an infinite range. Elecrotrostatic forces reduce significantly as charges move away small distances but are relatively strongly felt. We feel the forces pulling on us when we stretch rubber. But two large balls side by side will not be significantly attracted by their tiny gravitational forces!

4 0

3 years ago

What is the value of the composite constant (Gme,/r2e) to be multiplied by the mass of the object mo, in equation below:

Sedbober [7]

To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.

The equation for the gravitational force between the Earth and the object on the surface of the Earth is

$F_g = \frac{Gm_em_o}{r^2_e}$

Where,

G = Universal gravitational constant

$m_e$ = Mass of Earth

$r_e$ = Distance between object and center of earth

$m_o$ = Mass of Object

The equation for the gravitational pulling force on the object due to gravitational acceleration is

$F_g = m_o g$

Equation the two expression we have

$m_o g = \frac{Gm_em_o}{r_e^2}$

$g = \frac{Gm_e}{r_e^2}$

This the acceleration due to gravity which is composite constant.

Replacing with our values we have then

$g = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5.98*10^{24}kg)}{6378km(\frac{10^3m}{1km})^2}$

$g = 9.8m/s^2$

The value of composite constant is $9.8m/s^2$ . Here, the composite constant is nothing but the acceleration due to gravity which is constant always.

8 0

4 years ago

A boat that has a speed of 6km / h must cross a 200m wide river perpendicular to the current that carries a speed of 1m / s. Cal

ivanzaharov [21]

Answer:

a) 1.94 m/s

b) 120 m

Explanation:

Convert km/h to m/s:

6 km/h = 1.67 m/s

a) The final speed is found with Pythagorean theorem:

v = √((1.67 m/s)² + (1 m/s)²)

v = 1.94 m/s

b) The time it takes the boat to cross the river is:

t = (200 m) / (1.67 m/s)

t = 120 s

The displacement in the direction of the current is:

x = (1 m/s) (120 s)

x = 120 m

3 0

3 years ago

A ball at rest rolls across a frictionless floor at 12.0 m/s/s. How far will it travel in

professor190 [17]

Answer:

The distance, d travelled by the ball is 768 metres.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Hence, if we subtract the final speed from the initial speed and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{initial \; speed - final \; speed}{time}$

$a = \frac{v - u}{t}$

Where,

a is acceleration measured in $ms^{-2}$

v and u is initial and final speed respectively, measured in $ms^{-1}$

t is time measured in seconds.

Given the following data;

Acceleration = 12.0m/s²

Time, t = 8secs

Velocity =?

First, we would calculate its velocity;

$a = \frac{v - u}{t}$

Since the ball rolls at rest, initial velocity is zero (0).

$V = a * t$

$V = 12 * 8$

$Velocity = 96ms^{-1}$

We can now solve for the distance;

$Velocity = \frac{distance}{time}$

Therefore,

$Distance = velocity * time$

$Distance = 96 * 8$

Distance = 768m.

3 0

3 years ago

Which of the following events occurred FIRST in 1846?

Volgvan

"Elias Howe invents the sewing machine" is the one event among the following choices given in the question that occurred first in 1846. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that this is the answer that has actually come to your desired help.

3 0

3 years ago

Doe anyone get this ​

Doe anyone get this