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Brut [27]
3 years ago
10

Okaygoing offline byehave a great day​

Engineering
2 answers:
sweet-ann [11.9K]3 years ago
5 0

Answer:

by by tc.............. lol

olga nikolaevna [1]3 years ago
3 0

Answer:

bye tc

have a great day

✌✌✌✌✌✌

You might be interested in
Determine the time required for a car to travel 1 km along a road if the car starts from rest, reaches a maximum speed at some i
lbvjy [14]

Total time taken by car to travel 1 km distance is 48.2 seconds

Explanation:

Given data-

Total distance- 1 km= 1000m

Car starts from rest- Hence the initial velocity (u)= 0 m/s

Then, car accelerates at 1.5 m/s ²

Let us suppose with these acceleration car reaches the max speed of V

Car then decelerates at rate of 2 m/s ²

Finally, car comes to rest

We need to consider the question in two parts

Part 1= when car starts from rest and reaches the value V in the time tₐ at the distance s₁.

Part 2= When car starts from V and finally stops at 1 km mark in the time tₙ in distance 1000-s₁.

For the part 1

We know the formula  

v= u + a*tₐ

where v= final velocity

u- initial velocity

a= acceleration

tₐ= time period

At the starting u= 0  

Hence the equation reduces to V=0+1.5tₐ

Or V= 1.5tₐ                             Eq 1

We also know that s= u*tₐ+ ¹/₂*a*tₐ²

Where s₁= distance covered  (other symbols same meaning)

Since u=0   (u*tₐ=0)

s₁ = ¹/₂*1.5*tₐ²

s₁= ½* 1.5*tₐ²                    -------------Eq 2

Now considering Part 2

Here the case is deceleration hence the equation would change (symbols same)

v= V-a*tₙ     final velocity(v)=0 (car stops finally) & initial velocity (part 2)= V

V= a*tₙ

V=2*tₙ                                 -----------Eq 3

Similarly  

1000-s₁= V* tₙ+¹/₂*(-2) *(tₙ)²

1000-s₁= V* tₙ-tₙ²                      -------Eq 4

Comparing Eq 1 and Eq 3

V= 1.5tₐ  and V=2tₙ                                                              

1.5tₐ = 2 tₙ

tₐ=1.33 tₙ  

Using the above value of tₐ in Eq 1

V= 1.5 tₐ and tₐ= 1.33 tₙ

V= 2tₙ

Similarly from Eq 2 and putting the value of tₙ

s₁= ½*1.5*tₐ²      

s₁=  1.33*(tₙ)²

Substituting the above values in equation 4

1000-s₁= V* tₙ-tₙ²                      

1000- 1.33(tₙ)²=2*(tₙ)*(tₙ)- tₙ²

1000=2.33 (tₙ)²

tₙ=      1000/2.333    

tₙ= 20.7 sec

Similarly putting the value of tₙ in tₐ= 1.33 tₙ

tₙ= 27.5 sec

Hence total time is tₐ +tₙ  

T= 20.7+27.5= 48.2 sec                

8 0
3 years ago
How do we infer that there is
Katena32 [7]

Answer:

Not too far removed from Collingwood’s concern with the elimination of physical and moral force via social civilization are accounts of civilized society concerned with the management of violence, if only by removing it from the public sphere. Such a concern is extended in Zygmunt Bauman’s account of civilization to the more general issue of producing readily governable subjects. The “concept of civilization,” he argues, “entered learned discourse in the West as the name of a conscious proselytising crusade waged by men of knowledge and aimed at extirpating the vestiges of wild cultures” (1987, 93).

This proselytizing crusade in the name of civilization is worth considering further. Its rationale is not too difficult to determine when one considers Starobinski’s (1993, 31) assertion: “Taken as a value, civilization constitutes a political and moral norm. It is the criterion against which barbarity, or non-civilization, is judged and condemned.” A similar sort of argument is made by Pagden (1988, 33), who states that civilization “describes a state, social, political, cultural, aesthetic—even moral and physical—which is held to be the optimum condition for all mankind, and this involves the implicit claim that only the civilized can know what it is to be civilized.” It is out of this implicit claim and the judgments passed in its name that the notion of the “burden of civilization” was born. And this, many have argued, is one of the less desirable aspects and outcomes of the idea of civilization

6 0
3 years ago
The closed tank of a fire engine is partly filled with water, the air space above being under pressure. A 6 cm bore connected to
skelet666 [1.2K]

Answer:

The air pressure in the tank is 53.9 kN/m^{2}

Solution:

As per the question:

Discharge rate, Q = 20 litres/ sec = 0.02\ m^{3}/s

(Since, 1 litre = 10^{-3} m^{3})

Diameter of the bore, d = 6 cm = 0.06 m

Head loss due to friction, H_{loss} = 45 cm = 0.45\ m

Height, h_{roof} = 2.5\ m

Now,

The velocity in the bore is given by:

v = \frac{Q}{\pi (\frac{d}{2})^{2}}

v = \frac{0.02}{\pi (\frac{0.06}{2})^{2}} = 7.07\ m/s

Now, using Bernoulli's eqn:

\frac{P}{\rho g} + \frac{v^{2}}{2g} + h = k                  (1)

The velocity head is given by:

\frac{v_{roof}^{2}}{2g} = \frac{7.07^{2}}{2\times 9.8} = 2.553

Now, by using energy conservation on the surface of water on the roof and that in the tank :

\frac{P_{tank}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{tank} = \frac{P_{roof}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{roof} + H_{loss}

\frac{P_{tank}}{\rho g} + 0 + 0 = \0 + 2.553 + 2.5 + 0.45

P_{tank} = 5.5\times \rho \times g

P_{tank} = 5.5\times 1\times 9.8 = 53.9\ kN/m^{2}

4 0
3 years ago
Ok there........................................................................
Juliette [100K]

Answer:

ok THERE

Explanation:

4 0
3 years ago
For a Cu-Ni alloy containing 53 wt.% Ni and 47 wt.% Cu at 1300°C, calculate the wt.% of the alloy that is solid and wt.% of allo
Zina [86]

Answer:

Hello your question is incomplete attached below is the complete question

answer: wt.% of alloy that is solid = 61.5%

             wt.% of allot that is liquid = 38.5%

Explanation:

To determine the wt.% of the alloy that is solid

= \frac{R}{R +S } * 100

=  \frac{53-45}{58-45} * 100  = 61.5%

To determine the wt.% of the alloy that is liquid

= \frac{S}{S+R} * 100\\

= \frac{58-53}{58-45} *100 = 38.5%

attached below is a free hand sketch as well

7 0
3 years ago
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