Answer:
the total charge which crosses into the collector is 60 nC
Explanation:
Given the data in the question;
current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A
no charge was transferred in or out of the collector lead prior to t = 0
the current flow time t = 1 min = 60 sec
Now we write the relation between current, charge, and time;
i = dq / dt
where i is current, q is charge and t is time. { d refers to change }
Now,
q = 60 × 10⁻⁹ C
q = 60 nC
Therefore, the total charge which crosses into the collector is 60 nC
Answer:
The answer is "Choice b,c, and d".
Explanation:
The distillation would be the separation phase of working liquids that boil close to each other. Whenever the formulation is long-term, a much more fraction of a compound collected will have a lower boiling point than it would otherwise be. In other phrases, it'll be pulverized with both the lower level, also with the boiling point. Its structure of both the diluted volatile component may therefore include another cell's contaminants.
The Automation in which special-purpose automation is designed for only one complex product and it cannot be changed is Fixed Automation.
<h3>What is Fixed Automation?</h3>
Fixed Automation is an automation system in which the manufacturing processes remain the same after they have been configured. They cannot be easily altered and are also referred to as Hard Automation.
Companies that engage in the mass production of items use this automation system.
Learn more about Automation here:
brainly.com/question/11211656
Answer:
a) C_v = 1.005 KJ/kgK
b) C_v = 1005.000 J/kgC
c) C_v = 0.240 kcal/kgC
d) C_v = 0.240 Btu/lbmF
Explanation:
Given:
- constant-pressure specific heat C_v = 1.005 KJ/kgC
Find C_v in units of:
a) kJ/kg·K
b) J/g·°C
c) kcal/ kg·°C
d) Btu/lbm·°F
Solution:
a) C_v is Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass. Usually, it's the heat in Joules needed to raise the temperature of 1 gram of sample 1 Kelvin or 1 degree Celsius. Hence,
C_v = 1.005 KJ/kgK
b)
C_v = 1.005 KJ/kgC * ( 1000 J / KJ)
C_v = 1005.000 J/kgC
c)
C_v = 1.005 KJ/kgC * ( 0.239006 kcal / KJ)
C_v = 0.240 kcal/kgC
d)
C_v = 1.005 KJ/kgC * ( 0.947817 Btu / KJ) * ( kg / 2.205 lbm)*(Δ1 C / Δ1.8 F)
C_v = 0.240 Btu/lbmF