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2 years ago

9

Please help me with this question

1 answer:

Nat2105 [25]2 years ago

5 0

Answer:

The answer is c and the teacher helped me

Explanation:

i had help from the tescger and the assignment is done

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In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W

GrogVix [38]

Answer:

The shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

Explanation:

Given:

Temperature $T = 1273.15$ K

Initial Pressure $P_{1} = 1.8$ MPa

Final pressure $P_{2} = 0.1$ MPa

From the table superheated,

$h_{i} = 4635$ $\frac{K J}{Kg}$ and $h_{f} = 2706.54$ $\frac{K J}{Kg}$

Work done by shaft is,

$W = h_{f} - h_{i}$

$W = 2706.54 - 4635$

$W = -1928.46 \frac{kJ}{kg}$

But here efficiency is 0.56,

So work generated per kg is,

Work = $0.56 \times(- 1928.46)$

Work = $-1.3$ $\frac{MJ}{kg}$

Therefore, the shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

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3 years ago

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Goshia [24]

The answer would be 7

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4 years ago

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In which crash did the puck experience a stronger force? WHY/

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What is the area enclosed by the cycle area of the Carnot cycle illustrating on a T-s diagram?

gayaneshka [121]

Answer:

Heat

Explanation:

Carnot cycle:

Carnot cycle is the ideal cycle for all working engine .Carnot cycle all processes are reversible.It have fore process Out of two are constant temperature process and other two are isentropic process(reversible adiabatic).

We know that area under T-s diagram represents the heat.

So $Q=\int Tds$

From cycle we can say that

$q_{in}=T_2\left ( s_2-s_1 \right )$

$q_{out}=T_1\left ( s_2-s_1 \right )$

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4 years ago