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AfilCa [17]
3 years ago
7

Pick a subjectarea/field/topic that you are interested in. For each of the following Bonham- Carver uses of GIS give an example

from your chosen subject (for example, wetland ecology) Organetation Visualization Spatial Query. Combination Analysis, Prediction

Engineering
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer:

I hope following attachment will help you a lot!

Explanation:

You might be interested in
A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in^2. The
Minchanka [31]

Answers:

31.7 inches

Explanation:

Given:

Diameter = 3ft

Let D = Diameter

So, D = 3ft. (Convert to inches)

D = 3 * 12in = 36 inches

Coss-sectional area of the steel = 0.2in²

Gauge Pressure (P) = 4psi

Stress in Steel (σ)= 11.4ksi

Force in steel = ½ (Pressure * Projected Area)

Area (A) = 2 * Force/Pressure

Also, Area (A) = Spacing (S) * Wood Pipe Diameter

Area = Area

2*Force/Pressure = Spacing * Diameter

Substitute values I to the above expression

2 * Force / 4psi = S * 36 inches

Also

Force in steel (F) = Stress in steel (σ) × Cross-sectional area of the steel

So, F = 11.4ksi * 0.2in²

F = 11.4 * 10³psi * 0.2in²

F = 2.28 * 10³ psi.in²

So, 2 * Force / 4psi = S * 36 becomes

2 * 2.28 * 10³/4 = S * 36

S = 2 * 2.28 * 10³ / (4 * 36)

S = 4560/144

S = 31.66667 inches

S = 31.7 inches (approximated)

5 0
4 years ago
Water flows through a multisection pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s a
Alex_Xolod [135]

Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}

Where:

P_{1}, P_{2} - Pressures at the beginning and at the end of the current line, measured in kilopascals.

\rho - Water density, measured in kilograms per cubic meter.

v_{1}, v_{2} - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

Now, the pressure difference between these two points is:

P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}

If \rho = 1000\,\frac{kg}{m^{3}}, v_{1} = 3\,\frac{m}{s} and v_{2} = 2.1\,\frac{m}{s}, then:

P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}

P_{1} - P_{2} = -2295\,Pa

P_{1} - P_{2} = -2.295\,kPa (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

7 0
3 years ago
The bar DA is rigid and is originally held in the horizontal position when the weight W is supported from C. The wires are made
Rom4ik [11]

Answer:

W = 112 lb

Explanation:

Given:

- δb = 0.025 in

- E = 29000 ksi      (A-36)

- Area A_de = 0.002 in^2

Find:

Compute Weight W attached at C

Solution:

- Use proportion to determine δd:

                              δd/5 = δb/3

                              δd = (5/3) * 0.025

                              δd = 0.0417 in

- Compute εde i.e strain in DE:

                               εde = δd / Lde

                               εde = 0.0417 / 3*12

                               εde = 0.00116

- Compute stress in DE, σde:

                               σde = E*εde

                               σde = 29000*0.00116

                               σde = 33.56 ksi

- Compute the Force F_de:

                               F_de = σde *A_de

                               F_de = 33.56*0.002

                               F_de = 0.0672 kips

- Equilibrium conditions apply:

                               (M)_a = 0

                               3*W - 5*F_de = 0

                               W = (5/3)*F_de

                              W = (5/3)* 0.0672 = 112 lb

4 0
3 years ago
What plane is this? i want the model
myrzilka [38]

Answer:

I think that plane's name is

KLM ....Because you can see the mysterious Leter in the plane's

Forward and the back of the plane

4 0
2 years ago
*Avoid waiting in long drive-thru lines, for example, at fast-food restaurants or banks. Park your car and go in. *When possible
Lyrx [107]

Answer:

When possible, use public transportation, walk, or ride a bike

Explanation:

7 0
3 years ago
Read 2 more answers
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