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2 years ago

What is the slope of this graph?

Mathematics

1 answer:

Verdich [7]2 years ago

8 0

Answer:

6/12 or 1/2 which is 0.5

Step-by-step explanation:

I hope this is right, because I'm doing this stuff as well in class.

Slope is always rise over run. It is rising by 6 and it is running (going across) by 12. This fraction (6/12) can be simpiled to 1/2 and that can be narrowed down to 0.5.

Hope this is clear and correct.

You might be interested in

The face of the triangular concrete panel shown has an area of 22 square meters, and its base is 3 meters longer than twice its

Elodia [21]

Answer:

The length of the base is 11 meters.

Step-by-step explanation:

The diagram of the triangle is not shown; However, the given details are enough to solve this question.

Given

Shape: Triangle

Represent the height with h and the base with b

$b = 3 + 2h$

$Area = 22$

Required

Find the length of the base

The area of a triangle is calculated as thus;

$Area = \frac{1}{2} * b * h$

Substitute 22 for Area and 3 + 2h for b

The formula becomes

$22 = \frac{1}{2} * (3 + 2h) * h$

Multiply both sides by 2

$2 * 22 = 2 * \frac{1}{2} * (3 + 2h) * h$

$44 = (3 + 2h) * h$

Open the bracket

$44 = 3 * h + 2h * h$

$44 = 3h + 2h^2$

Subtract 44 from both sides

$44 - 44 = 3h + 2h^2 - 44$

$0 = 3h + 2h^2 - 44$

Rearrange

$0 = 2h^2 +3h - 44$

$2h^2 +3h - 44 = 0$

At this point, we have a quadratic equation; which is solved as follows:

$2h^2 +3h - 44 = 0$

$2h^2 + 11h - 8h - 44 = 0$

$h(2h + 11) - 4(2h + 11) = 0$

$(h - 4)(2h + 11) = 0$

Split the above

$(h - 4) = 0\ or\ (2h + 11) = 0$

$h - 4 = 0\ or\ 2h + 11 = 0$

Solve the above linear equations separately

$h - 4 = 0$

Add 4 to both sides

$h - 4 + 4 = 0 + 4$

$h = 0 + 4$

$h = 4$ ---- First value of h

$2h + 11 = 0$

Subtract 11 from both sides

$2h + 11 - 11 = 0 - 11$

$2h = 0 - 11$

$2h = -11$

Divide both sides by 2

$\frac{2h}{2} = -\frac{11}{2}$

$h = -\frac{11}{2}$ ------ Second value of h

Since height can be negative, we'll discard $h = -\frac{11}{2}$

Hence, the usable value of height is $h = 4$

Recall that $b = 3 + 2h$

Substitute 4 for h

$b = 3 + 2(4)$

$b = 3 + 8$

$b = 11$

Hence, the length of the base is 11 meters

3 0

3 years ago

Carol gave a 15 deposit on a diamond bracelet. The deposit was $73.50. What was the cost of the bracelet?

leva [86]

You probably meant 15%
if so,

$\frac{73.50}{.15} = 490$

4 0

3 years ago

Find the area of shaded region

Anastaziya [24]

Answer: 107 units.

Step-by-step explanation: To find the area of the first box, you multiply the side lengths, which in this case are 5 by 7 to get 35. Then you find the area of the second box by multiplying 8 * 10 which is 80 so the total area of everything is 115 units. Then you subtract the non - shaded region which is 2 * 4 units. So after subtracting 115 - 8, you get your final answer of 107 units.

4 0

3 years ago

Read 2 more answers

a) The mean age of graduate students at a University is at most 31 y ears with a standard deviation of two years. A random sampl

kari74 [83]

Answer:

A.)

H0: μ ≤ 31

H1: μ > 31

B.)

H0: μ ≥ 16

H1: μ < 16

C.)

Right tailed test

D.)

If Pvalue is less than or equal to α ; we reject the Null

Step-by-step explanation:

The significance level , α = 0.01

The Pvalue = 0.0264

The decision region :

Reject the null if :

Pvalue < α

0.0264 > 0.01

Since Pvalue is greater than α ; then, we fail to reject the Null ;

Then there is no significant evidence that the mean graduate age is more Than 31.

B.)

H0: μ ≥ 16

H1: μ < 16

Null Fluid contains 16

Alternative hypothesis, fluid contains less than 16

One sample t - test

C.)

Null hypothesis :

H0 : μ ≤ 12

. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.

Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12

d.)

If Pvalue is less than or equal to α ; we reject the Null.

3 0

2 years ago

Given that f(x) = x^2-3/2

AfilCa [17]

Answer:

368<939`01^9292^91 ibtimes

6 0

2 years ago