Help I was absent when she taught this

Solve the inequality 47.75 + x < 50 to determine how much more weight can be added to Li's suitcase without going

ehidna [41]

Answer:

Answer Choice A

Step-by-step explanation:

I took this assignment

(please give brainliest)

8 0

3 years ago

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A spheres radius is multiplied by 2. How is it’s surface area affected

dexar [7]

Answer:

The surface area is multiplied by 3.

Step-by-step explanation:

If r is the radius of a sphere its surface area = 4(pi)r^2. If the radius is doubled then its surface area = 4(pi)(2r)^2 = 4*4(pi)r^2. So the surface area becomes 4-fold or the increase in surface area is 300%.

3 0

3 years ago

Select all of the coefficients in the expression.

WARRIOR [948]

12, 2, 5, 4, 7
The coefficients are the numbers that are in front of the letters

7 0

3 years ago

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Which one is correct

Alexandra [31]

Answer:

i believe its false good Sir

6 0

2 years ago

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago