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Rzqust [24]
2 years ago
8

in science class, Marco recorded numbers. from an experiment as 12.87 12.13 12.5 and 12.08 which numbers are closer to 12 ? whic

h are closer to 13?
Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

Answer:

12.87, 12.5  is closer to 13

12.08, 12.13  is closer to 12

Step-by-step explanation:

Least to Greatest:

12

  • 12.08
  • 12.13
  • 12.5
  • 12.87

13

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−3(y+5)=15 someone please help me with this question my assignment is already late
AnnyKZ [126]

Answer: -10

Step-by-step explanation:

Simplifying

-3(y + 5) = 15

Reorder the terms:

-3(5 + y) = 15

(5 * -3 + y * -3) = 15

(-15 + -3y) = 15

Solving

-15 + -3y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + -3y = 15 + 15

Combine like terms: -15 + 15 = 0

0 + -3y = 15 + 15

-3y = 15 + 15

Combine like terms: 15 + 15 = 30

-3y = 30

Divide each side by '-3'.

y = -10

Simplifying

3 0
3 years ago
Fill in the blanks below using the word bank.
Charra [1.4K]

M is the slope.

B is the y-intercept

The constant of proportionality is the ratio between two directly proportional quantities.

7 0
3 years ago
Read 2 more answers
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
Read 2 more answers
The condition proves that triangle ABC and triangle EFG are congruent by the SAS criterion. If AB does not equal EF the criterio
andrezito [222]
If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G are not equal :
angle C ≠ angle G
5 0
3 years ago
I hope you guys can see the question, if not just let me know
QveST [7]

Answer:

The correct answer is 6.

Step-by-step explanation:

When translating and reflecting figures, the shape remains the same. So, the side of 2x-4 is corresponding to the side of 8 and they are equal to each other.

To solve, set up an equation like this to find x:

2x-4=8

Then, add 4 to both sides of the equation:

2x=12

The goal is to get x by itself and in order to do that, divide both sides by 2:

x=6

The value of x is 6. I hope this helps! ☺

3 0
4 years ago
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