You want to find the number of visits IN BETWEEN 12:30 PM and 6:45 PM
there some visits already recorded before 12:30. These visits are visits that you want to exclude but are included in the TOTAL visits
Before 12:30 the website has 1200 visits and at 6:45 the website has 14000.
You can do 14000-1200 to find the number of visits in the time frame between 12:30 and 6:45
ANSWER 12800 visits
4•4=16
12•5=60. That’s the answer
Pretty sure it’s 2 and 4. A unit rate is usually something to one 1. So 1 would be in the denominator.
The distributive property says that a(b+c)= ab+ac
3(2y-7)= 3(2y)+ 3(-7)
Final answer: 6y-21
