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Rasek [7]
3 years ago
14

How do you find percentages?

Mathematics
1 answer:
REY [17]3 years ago
4 0

Answer:

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100. The formula used to calculate percentage is: (value/total value)×100%.

Step-by-step explanation:

~Inosuke Hashibria~

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Use the properties of exponents to rewrite the expression.<br> (-3yz)(-3yz)(-3yz)(-3yz)
Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0
3 years ago
Which is equivalent sin^-1 (cos(pi/2))?Give your answer in radians
NNADVOKAT [17]

Answer:

Given the expression: \sin^{-1}(\cos(\frac{\pi}{2}))

Let the value of the given expression in radians be \theta

then;

\sin^{-1}(\cos(\frac{\pi}{2})) =\theta

\cos \frac{\pi}{2} = \sin \theta              ......[1]

We know the value of \cos \frac{\pi}{2} = 0

Substitute the given value in [1] we have;

\sin \theta = 0

Since, the value of \sin \theta is 0, therefore, the value of \theta is in the form of:

\theta = n\pi ; where n is the integer.

At n =0, 1 and 2, {Since, n is the integer}

Value of  \theta =0, \pi and 2\pi

therefore, the answer in radians either   0 , \pi or 2\pi


6 0
4 years ago
Read 2 more answers
What is the value of the expression when d=3. 7d²+10 (answer choice A.63 B.52 C.31 D.73 )
devlian [24]
You have to replace d woth 3 in formula
7d^2+10=7*(3)^2+10=7*9+10=63+10=73
d is the correct answer
6 0
4 years ago
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How many two thirds are in 42?
noname [10]
28, by the way you could’ve just used a calculator
7 0
4 years ago
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I need help answering this question. Any ideas on what it could be?
Lesechka [4]
Is this for a test/exam?
4 0
3 years ago
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