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Arisa [49]
3 years ago
13

The distance between tow objects is increased by 3 times the original distance. How will this change the force of attraction bet

ween the two objects?
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

force of attraction will be increased by 9

Explanation:

force of attraction is inversely proportional to square of distance

i.e F= 1/R²

F=1/3R²

F=1/9R

  • multiply both side by 9

9×F= 9×1/9R

9F= 1/R

so force of attraction is 9 times

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\\ \maltese \:  \:  \:  \: \large{\underline{\underline{\pmb{ \textbf{\textsf{\color{green}{To  \: Find \:  :}}}}}} } \\  \\

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\\  \maltese \:  \:  \:  \: \large{\underline{\underline{\pmb{ \textbf{\textsf{\color{aqua}{Solution \:  :}}}}}} } \\  \\

★ <u>Calculating the kinetic energy</u>;

\\  \maltese \:  \:  \:  \: \large{\underline{\underline{\pmb{ \textbf{\textsf{\color{hotpink}{using \: formula \:  :}}}}}} } \\  \\

\red\bigstar { \underline{ \underline{\underline{\boxed{\color{blue}{\sf{ \:Kinetic  \:  \: energy  \:   =  \frac{1}{2}  \:  \: m \: v \:  {}^{2}   }}}}}} }\\  \\

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\\\\\sf \implies \: \:Kinetic  \:  \: energy  \:   =  \frac{1}{2}  \:  \: m \: v \:  {}^{2} \\

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\\\sf \implies \: \:Kinetic  \:  \: energy  \:   =  \frac{1}{ \cancel{2}} \:  \times   \:   \cancel {4,500 }\:  \times \: 400\\

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