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Arisa [49]
3 years ago
13

The distance between tow objects is increased by 3 times the original distance. How will this change the force of attraction bet

ween the two objects?
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

force of attraction will be increased by 9

Explanation:

force of attraction is inversely proportional to square of distance

i.e F= 1/R²

F=1/3R²

F=1/9R

  • multiply both side by 9

9×F= 9×1/9R

9F= 1/R

so force of attraction is 9 times

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Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is v=\frac{d}{t}, where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is d=v\cdot t

Now, the distance equation for the man would be:

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The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

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For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

d_{man}=d_{dog}

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1.6\cdot t=3\cdot t-5.4

1.4\cdot t=5.4

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The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

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d_{man}=6.1714m

Finally, the dog catches up with the man 6.1714m later.

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