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Vika [28.1K]
2 years ago
6

what additional reaction product would result if naoh was used as a base in this reaction instead of k2co3?

Chemistry
1 answer:
AnnZ [28]2 years ago
7 0

Answer:

What reaction product would result if NaOH was used as a base in this reaction instead of K2CO3? If sodium hydroxide was used as the base of the reaction, then the reaction product formed would be an ethyl alcohol because it would undergo a hydrolysis reaction with addition of iodoethane

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There are _____ major plates that make up the most of the continents and the Atlantic and Pacific Ocean.
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Answer and Explanation:

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Together, the crust and the upper part of the mantle form the lithosphere, Earth's solid outer shell. This rocky, brittle layer is broken up into seven major and several minor tectonic plates (also known as lithospheric plates) that fit together like puzzle pieces.

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6 0
3 years ago
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How many elements are in P4I10
artcher [175]

Answer:

2

Explanation:

P: Phosphorous

I: Iodine

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6 0
3 years ago
The fact that gold is not brittle is a
Feliz [49]

Explanation:

Brittleness is a characteristic that describes chalk. Its color and shape also describe the chalk. Any such characteristic of a material that you can observe without changing the substances that make up the material is a physical property

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6 0
3 years ago
What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0
3 years ago
What does a positive H look like on a potential energy diagram?
Iteru [2.4K]

Answer:

D because i did this last week and got it right.

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