Question

Carbon-14 emits beta radiation and decays with a half-life (t ) of 5730 years. Assume that you start with a mass of 6.00 × 10^–12 g of carbon 14. How many grams of the isotope remains at the end of three half-lives?

Answer 1

Answer:

did you ever find the answer

Explanation:

Answer 2

Answer: $0.75\times 10^{-12}$

Explanation:

Formula used :

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives = ?

$a_o$ = Initial amount of the reactant = $6\times 10^{-12} g$

n = number of half lives = 3

Putting values in above equation, we get:

$a=\frac{6\times 10^{-12} }{2^3}$

$a=\frac{6\times 10^{-12} }{8}$

$a=0.75\times 10^{-12}$

Therefore, the amount of carbon-14 left after 3 half lives will be $0.75\times 10^{-12}g$