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brilliants [131]

3 years ago

6

Carbon-14 emits beta radiation and decays with a half-life (t ) of 5730 years. Assume that you start with a mass of 6.00 × 10^–1

2 g of carbon 14. How many grams of the isotope remains at the end of three half-lives?

2 answers:

ludmilkaskok [199]3 years ago

8 0

Answer:

did you ever find the answer

Explanation:

andrey2020 [161]3 years ago

4 0

Answer: $0.75\times 10^{-12}$

Explanation:

Formula used :

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives = ?

$a_o$ = Initial amount of the reactant = $6\times 10^{-12} g$

n = number of half lives = 3

Putting values in above equation, we get:

$a=\frac{6\times 10^{-12} }{2^3}$

$a=\frac{6\times 10^{-12} }{8}$

$a=0.75\times 10^{-12}$

Therefore, the amount of carbon-14 left after 3 half lives will be $0.75\times 10^{-12}g$

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a bond where electrons are transferred from one atom to another, resulting in charge imbalance in each atom. a bond where electr

Illusion [34]

Answer:

1. A bond where electrons are transferred from one atom to another, resulting in charge imbalance in each atom is called ionic bonding.

2. A bond where electrons are equally shared, resulting in equal numbers of electrons orbiting each atom is called non-polar covalent bond.

3. A bond where electrons are unequally shared, resulting in more electrons orbiting certain atoms than others is called a polar covalent bond.

4. A bond where the electronegativity differences between the atoms within a molecule result in the partially positive atoms of one molecule attracting the partially negative atoms of other molecules is called polar bond and it is part of the covalent bonds.

Explanation:

1. In ionic bonding process, electrons are enterely transferred from one atom to another either losing or gaining negatively charged electrons, and the reacting atoms form ions. A charge imbalance is caused then by the oppositely charged ions, when attracted to each other by electrostatic forces, the basis of the ionic bond.

2. A non-polar covalent bond is occurs when two atoms have same electron afinity to share their electrons equally. The closer the values of their electron affinity, the stronger the attractionis. This is created in diatomic elements or gas molecules.

3. A polar covalent bond is a type of chemical bond where two electrons are unequally shared between two atoms, electrons are not equally shared because one atom spends more time with the electrons than the other atom, resulting in more electrons orbiting certain atoms than others.

4. The polar bond is a type of covalent bonds. This bonds depends on atoms´electronegativity differences. If an atom is less electronegative, it means that the electron distribution or charge is unevenly distributed or polarized and then it becomes partially positive.

8 0

3 years ago

What holds the hydrogen and oxegyn atoms together in a water molecule

dem82 [27]

Answer: Hydrogen bonds

Explanation: Hydrogen bonds allow two molecules to link together temporarily. Water molecules are made up of two hydrogen atoms and one oxygen atom, held together by polar covalent bonds.

7 0

2 years ago

How many bromine atoms are present in 37.9 g of CH2Br2?

VARVARA [1.3K]

Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

CH2Br2 = 37.9 g

MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

174 g of CH2Br2 ------------------ 160 g of Br2

37.9 g of CH2Br2 --------------- x

x = 37.9 x 160/174 = 34.85 g of Br

1 mol of Br ----------------- 160 g Br2

x ---------------- 174 g Be2

x = 174 x 1 /160 = 1.088 mol of Br2

1 mol of Br ----------------- 6.023 x 10 ²³ atoms

1.088 mol of Br ------------- x

x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

4 0

2 years ago

I need help due today!!!!!

Hitman42 [59]

Answer:

A. 5 g/mL

Explanation:

5 0

2 years ago

Read 2 more answers

Calculate the maximum numbers of moles and grams of H₂S that can form when 158 g of aluminum sulfide reacts with 131 g of water:

Phantasy [73]

What is Chemical Reaction?

A chemical reaction is the chemical transformation of one set of chemical components into another.

Main Content

Mass of aluminium sulfide is 158g

Mass of water is 131g

The chemical reaction: $Al_{2}S_{3} +H_{2}O _\to Al(OH)_{3} + H_{2}S$

First, balance the chemical equation

$Al_{2}S_{3} + 6H_{2}O \to 2Al(OH)_{3} + 3H_{2}S$

Aluminium sulfide has a molar mass of 150.16 g/mol and water has a molar mass of 18.02 g/mol. As a result, the moles of aluminum sulfide are computed as follows:

$n_{Al_{2}S_{3} } = \frac{Mass}{Molar mass}\\n_{Al_{2} S_{3} } = \frac{158g}{150.16g/mol} \\n_{Al_{2}S_{3} }=1.05 mol$

From the chemical reaction , the ratio of molar is 3mol $H_{2}S/1 mol Al_{2}S_{3}.$ So, the moles of hydrogen sulfide are:

$n_{H_{2} O} =\frac{131g}{18.02g/mol}$

= 7.26mol

From the chemical reaction, the molar ratio is 3 mol $H_{2}S/6$ mol $H_{2}O.$ So, the moles of hydrogen sulfide are:

Moles of $H_{2}S$ formed = 7.26 mol $H_{2}O \times \frac{3 mol H_{2}S }{6 mol H_{2} O} }$

Th liming reactant is $Al_{2}S_{3}$ beacuse the mass of $Al_{2}S_{3}$ forms less product than water. Therefore, the maximum number of moles of $H_{2}S$ is 3.15 mol. We know that molar mass of $H_{2}S$ is 34.10g/mol. So, the maximum mass of $H_{2}S$ formed is,

$m_{H_{2}S } = n_{H_{2}S } \times$ Molar mass of $H_{2}S$

= 3.15 mol $\times$ 34.10g/mol

= 107.4g

Now, multiplying the number of moles of $Al_{2}S_{3}$ by the molar ratio between $Al_2S_3$ and $H_2O$ which is 6mol $H_2O/1mol$ $Al_2S_3$ we get the number of moles of $H_2O$ reacted.

Moles of $H_2O$ reacted = 1.05 mol $Al_{2}S_3 \times \frac{6 mol H_2O}{1 mol Al_2S_3}$

= 6.31 mol $H_2O$

The mass of $H_2O$ is,

$m_{H_{2} O}$ = 6.31 mol $\times$ 18.02g/ mol

= 114g

On subtracting, the mass of $H_2O$ reacted from the given mass of $H_2O$ is,

$m_{H_2O}$ = (131-114)g

= 17g

Hence, the excess remaining reactant is 17g

To learn more about Chemical Reaction

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8 0

1 year ago