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Amanda [17]
3 years ago
12

Use the chemical equation and the bond diagram to answer the question.

Chemistry
1 answer:
lesantik [10]3 years ago
4 0

Answer:

it should be  0-0

Explanation:

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How many grams of carbon dioxide are produced from 0.98 mol of Fe3O4?
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Hello

the answer is 43.129310000000004

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2. Which is a true statement about a zero net force?
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Answer: the correct option is A (A zero net force causes no change to an object's

motion.)

Explanation:

Force is a vector quantity that causes an object to accelerate or change velocity when pushed or pulled. While a NET FORCE can be defined as the combination of all forces acting on an object which is equally capable of accelerating the object.

When a NET FORCE is equal to zero( that is zero net force),there will be no change to an object's motion. When the net force of an object is equal to zero , it shows the object is in either static equilibrium( the objects velocity is zero) or dynamic equilibrium(where the object is moving at constant velocity). In both cases, the object remains motionless because the net forces is equal to zero.

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3 years ago
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A single atom of oxygen cannot be subdivided into simpler substances by any physical or chemical means. Therefore, it is:
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3 years ago
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Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid with water
Vera_Pavlovna [14]

Answer:

<h3>C6H5CO2H (aq) + H2O (l) _C6H5CO2<em>-</em><em> </em><em>+</em><em> </em><em>H3O</em></h3>
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3 years ago
For the reaction: 3 KClO3 to 3 KCL + 4O2, How many miles of potassium chloride are produced from 9.3 grams of potassium chloride
Valentin [98]

5.7 g of KCl is produced.

<u>Explanation:</u>

First we have to write the balanced equation as,

2 K C l O_{3} \rightarrow 2 K C l+3 O_{2} \uparrow

Then we have to find the moles of potassium chlorate as,

Moles of $K C l O_{3}=9.3 g$ of $K C l O_{3} \times \frac{1 \text { mol of } K C l O_{3}}{122.55 g K C l O_{3}}=0.076$ moles

Then we have to find the moles of KCl as,

Moles of $\mathrm{KCl}=0.076$ moles of $\mathrm{KClO}_{3} \times \frac{2 \text { mol of } \mathrm{KCl}}{2 \text { mol } \mathrm{KClo}_{3}}=0.076$ moles

From the moles of KCl, we have to find the mass using its molar mass by multiplying them as,

\text { Mass of } \mathrm{KCl}=0.076 \text { mol } \times 74.55 \frac{g}{\mathrm{mol}}=5.7 \mathrm{g} \text { of } \mathrm{KCl}

3 0
3 years ago
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