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Gwar [14]
3 years ago
11

The _________ __________ is the bottom number on each element?

Chemistry
1 answer:
kati45 [8]3 years ago
7 0
The full chemical symbol for an element<span> shows its mass </span>number<span> at the top, and its atomic </span><span>number at the bottom</span>

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The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu
Inessa [10]

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

^{A}_{Z}X \rightarrow ^{2}_{1}H  

The mass defect can be calculated by using the following equation:

\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}

Where:

Z: is the number of protons = 1

A: is the mass number = 2      

m_{p}: is the proton's mass = 1.00728 amu  

m_{n}: is the neutron's mass = 1.00867 amu

m_{a}: is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!  

5 0
3 years ago
Read 2 more answers
I need HELP!!!<br><br> Do the benefits of nuclear power outweigh the risks?
Georgia [21]
While there is no such thing as 100 percent safe, having nuclear energy is much safer than you think. It's thousands of times safer than conventional coal and other fossil-fuel-derived energy, not to mention the specter of environmental disaster from continued use of carbon-based energy sources.
3 0
3 years ago
Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
Urgent please help me!!!
nikitadnepr [17]

Explanation:

A. lithium hydroxide =LiOH

B. sodium cyanide =NaCN

C. Magnesium nitrate = Mg(NO3)2

D. Barium sulfate = BaSO4

E. Aluminum nitride = AlN

F. Potassium phosphate = KH2PO4

G. Ammonium bromide = NH4Br

H.Calcium carbonate = CaCO3

5 0
3 years ago
A 0.227 mol chunk of dry ice (solid CO2) changes to gas. What is the volume of that gas measured at 27 °C and 740 mmHg?
jeka57 [31]

Answer:

Explanation:3.2 ft 2 fti2 ft 4 ft ft2

4 0
2 years ago
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