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Gwar [14]
3 years ago
11

The _________ __________ is the bottom number on each element?

Chemistry
1 answer:
kati45 [8]3 years ago
7 0
The full chemical symbol for an element<span> shows its mass </span>number<span> at the top, and its atomic </span><span>number at the bottom</span>

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Four animals were fleeing from a wildfire. All of them were running at a speed of 30 miles per hour. Which one has the greatest
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Answer: I don’t know lol

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A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
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c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

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1. Using the Slater rule, determine the effective nuclear charge of platinum.
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Answer:

Z* = 3.55

Explanation:

Slater rule says that:

Z*= Z - S

Z* be the nuclear effective charge

Z is the nuclear charge

S is the shielding constant

First we write the electronic configuration of platinum:1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 4f^{14} 5d^{9} 6s^{1}

The first Slater rule says that we need to group:

(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

For our case, we have an electro that is in ns, so the rule says that

-electrons within same group shield 0.35, except the 1s which shield 0.30

-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

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3 years ago
Lead (11) oxide dissolves in both
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Answer:

bacic

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