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Gwar [14]
3 years ago
11

The _________ __________ is the bottom number on each element?

Chemistry
1 answer:
kati45 [8]3 years ago
7 0
The full chemical symbol for an element<span> shows its mass </span>number<span> at the top, and its atomic </span><span>number at the bottom</span>

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An organic chemist measures the temperature T of a solution in a reaction flask. Here is the result. T = 149.206 °C Convert T to
jolli1 [7]

<u>Answer:</u> The temperature of the solution in Kelvins is 422.356 K

<u>Explanation:</u>

Temperature is defined as the measure of coldness or hotness of a body. It also determines the average kinetic energy of the particles in a body.

This term is expressed in degree Celsius, degree Fahrenheit and Kelvins. All these units are interchangeable.

The S.I unit of temperature is Kelvins.

We are given:

Temperature of a solution = 149.206^oC

Conversion used to convert degree Celsius and Kelvins is:

T(K)=[273.15+T(^oC)]

T(K)=273.15+149.206\\T(K)=422.356K

Hence, the temperature of the solution in Kelvins is 422.356 K

6 0
3 years ago
i don't need these solved I just need the steps to solve it and. what these problems in chemistry would be called so I can look
wolverine [178]

The answers are as follows,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr

<u>Explanation:</u>

All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.

It can be expressed as follows,

                      P1V1 = P2V2

Rearranging the above expression, we get,

                     $ V2 = \frac{P1V1}{V2}

1) The first case can be solved as,

     $V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}

2) The second case can be solved as,

       $V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L

3) The third case can be solved as,

     $P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}

Thus the answers for all the three cases are found as,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr respectively

6 0
3 years ago
For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4? 4 9 10 16 32
Ghella [55]
I believe the answer is 32.
Hope that helps.
8 0
3 years ago
Read 2 more answers
How can you tell if a compound is an acid or base?
garri49 [273]
By there pH . a pH below 7 is acidic . Above 7 is basic. If it’s right at 7 it’s neutral.
6 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands
Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

E=\frac{R_y}{n^2}

R_y=2.18\times 10^{-18} J =  Rydberg energy

n =  principal quantum number of the orbital

Energy of 11th orbit = E_{11}

E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J

Energy of 10th orbit = E_{10}

E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J

=E'=0.38\times 10^{-20} J

\lambda =\frac{hc}{E'} (Planck's' equation)

\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}

\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

3 0
3 years ago
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