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3 years ago

What can be correctly concluded from this experiment?

Physics

2 answers:

solong [7]3 years ago

5 0

1

Step by step explanation: 1

Brainlist?????

Leona [35]3 years ago

3 0

1 because idek just go with it

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The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i

Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius= $r=\frac{d}{2}=\frac{2.3}{2}=1.15 m$

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency= $\frac{1200}{60}=20 Hz$

1 minute=60 seconds

Angular velocity= $\omega=2\pi f$

Angular velocity= $2\times \frac{22}{7}\times 20=125.7 rad/s$

b.We have to find the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac.

$v=r\omega=1.15\times 125.7=144.56 m/s$

c.Centripetal acceleration= $\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2$

Centripetal acceleration== $\frac{18170.56\times g}{9.81}=1852.25 g m/s^2$

7 0

4 years ago

One end of a horizontal spring with force constant 130.0 Ni'm is attached to a vertical wall. A 4.00-kg block sitting on the flo

tekilochka [14]

Answer:

Explanation:

When the spring is compressed by .80 m , restoring force by spring on block

= 130 x .80

= 104 N , acting away from wall

External force = 82 N , acting towards wall

Force of friction acting towards wall = μmg

= .4 x 4 x 9.8

= 15.68 N

Net force away from wall

= 104 -15.68 - 82

= 6.32 N

Acceleration

= 6.32 / 4

= 1.58 m / s²

It will be away from wall

Energy released by compressed spring = 1/2 k x²

= .5 x 130 x .8²

= 41.6 J

Energy lost in friction

= μmg x .8

= .4 x 4 x 9.8 x .8

= 12.544 J

Energy available to block

= 41.6 - 12.544 J

= 29 J

Kinetic energy of block = 29

1/2 x 4 x v² = 29

v = 3.8 m / s

This will b speed of block as soon as spring relaxes. (x = 0 )

4 0

3 years ago

Which effects result from the influence of media and technology on children

Salsk061 [2.6K]

Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression

6 0

4 years ago

A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s

BARSIC [14]

Answer:

The wavelength is $\lambda_R = 649 *10^{-9}\ m$

Explanation:

From the question we are told that

The wavelength of the red laser is $\lambda_r = 632.8 \ nm = 632.8 *10^{-9}\ m$

The spacing between the fringe is $y_r = 6.00\ mm = 6.00*10^{-3} \ m$

The spacing between the fringe for smaller laser point is $y_R = 6.19 \ mm = 6.19 *10^{-3} \ m$

Generally the spacing between the fringe is mathematically represented as

$y = \frac{D * \lambda }{d}$

Here $D$ is the distance to the screen

and d is the distance of the slit separation

Now for both laser red light light and small laser point D and d are same for this experiment

$\frac{y_r}{\lambda_r} = \frac{D}{d}$

=> $\frac{y_r}{\lambda_r} = \frac{y_R}{\lambda_R}$

Where $\lambda_R$ is the wavelength produced by the small laser pointer

$\frac{6.0 *10^{-3}}{ 632.8*10^{-9}} = \frac{ 6.15 *10^{-9}}{\lambda_R}$

=> $\lambda_R = 649 *10^{-9}\ m$

7 0

3 years ago

Define oxygen and it's uses

Svetradugi [14.3K]

Answer:

Oxygen is a colorless, odorless gas and it is a life supporting component of the air.

It can be used commonly for one of these 3 things:

1. Respiration

2. Metallurgy

3. Rocketry

Hope it helps! : )

3 0

4 years ago