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sesenic [268]
3 years ago
8

What can be correctly concluded from this experiment?

Physics
2 answers:
solong [7]3 years ago
5 0
1


Step by step explanation: 1

Brainlist?????
Leona [35]3 years ago
3 0
1 because idek just go with it
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Define second class lever​
Aleks04 [339]

Answer:

Please find detailed explanation of second class levers below

Explanation:

Levers are one of the classes of machine that possesses three levels namely: first class, second class and third claas. A second class lever is the level of levers in which the load (L) is in between the pivot (F) and the effort (E).

Examples of second class levers include; wheelbarrow, a bottle opener etc. In the bottle opener for example, the bottle lid (load) is in between the pivot of the opener and the hand opening it (effort).

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3 years ago
What do the sound waves made by the bell carry to your ear
ad-work [718]

Answer:

When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.

Explanation:

3 0
1 year ago
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Is every section of the chromosome active? Why or why not?
Nat2105 [25]
Yes, every section of the chromosome is active because 1 chromosome can hold many genes that works together to make proteins
4 0
3 years ago
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In a single-slit diffraction experiment, the width of the slit through which light passes is increased. What happens to the widt
kvasek [131]

Answer:

the width of the central bright fringe reduces

Explanation:

In a single-slit diffraction experiment, if the width of the slit through which light passes is increased, then the width of the central bright fringe reduces.

Example, if the width of the slit is doubled, then the width of the central bright fringe will be halved.

Thus, for single-slit diffraction experiment, increase in the width of the slit through which light passes will result in a corresponding decrease in the width of the central bright fringe.

3 0
3 years ago
According to recent typical test data, a Ford Focus travels 0.240 mi in 19.3 s, starting from rest. The same car, when braking f
Anit [1.1K]

Answer:

Explanation:

a )

While breaking initial velocity u = 62.5 mph

= 62.5 x 1760 x 3 / (60 x 60 )  ft /s

= 91.66 ft / s

distance trvelled s = 150 ft

v² = u² - 2as

0 = 91.66²  - 2 a x 150

a = - 28 ft / s²

b ) While accelerating initial velocity u = 0

distance travelled s = .24 mi

time = 19.3 s

s = ut + 1/2 at²

s is distance travelled in time t with acceleration a ,

.24 = 0 + 1/2 a x 19.3²

a = .001288 mi/s²

= 2.06 m /s²

c )

If distance travelled s = .25 mi

final velocity v = ? a = .001288 mi / s²

v² = u² + 2as

= 0 + 2 x .001288 x .25

= .000644

v = .025 mi / s

= .0025 x 60 x 60 mi / h

= 91.35 mph .

d ) initial velocity u = 59 mph

= 86.53 ft / s

final velocity = 0

acceleration = - 28 ft /s²

v = u - at

0 = 86.53 - 28 t

t = 3 sec approx .

4 0
3 years ago
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