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4 years ago

Which of the following waves have the longest wavelengths?

Physics

2 answers:

scoray [572]4 years ago

8 0

Answer:

Radio waves have the longest wavelenghts.

Explanation:

Radio waves are the most low-frequency form of electromagnetic radiation. Radio waves have frequencies from 300 GHz down to 3 kHz, and corresponding wavelengths between 1 millimeter and 100 kilometers.

Radio waves can be created naturally by natural phenomena such as lightning, or astronomical objects. They can also be generated artificially and are used for fixed and mobile radio communications, broadcasting, radar and other navigation systems, communications satellites, telematic networks and many other applications.

Paladinen [302]4 years ago

7 0

Radio waves have the longest wavelengths

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A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat

Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

$s = v_0t + gt^2/2$

where $v_0$ is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

$3.5 = v_01.1 - 9.81*1.1^2/2$

$3.5 = 1.1v_0 - 5.94$

$1.1v_0 = 3.5 + 5.94 = 9.44$

$v_0 = 9.44 / 1.1 = 8.58 m/s$

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

$v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s$

So they keys would have a downward speed of 2.211 m/s

5 0

3 years ago

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Snezhnost [94]

Frozen water has move volume than water in liquid form

8 0

3 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across the street is 78°, and the angle

Papessa [141]

The answer would be 371.16 ft.

Refer to the diagram for the scenario. The drawing is not to scale.

Notice the diagram that you will find to adjacent right triangles. All you need to do is first solve for the needed side of one triangle, by using one side.

It sounds confusing I know, but let's do this step by step.

Angle of depression is 15°.

We use this first because we do not have enough data to use the angle of elevation.

To get the adjacent side, we use the trigonometric function TOA which means:

$tan\theta= \dfrac{opposite}{adjacent}$

We use the height of the first building as our reference, so our given will be:

Opposite = 20ft

θ = 15°

Now we put that into our formula:

$tan\theta= \dfrac{opposite}{adjacent}$

$Tan15 = \dfrac{20ft}{adjacent}$

$adjacent = \dfrac{20ft}{Tan15}$

Adjacent = 74.64 ft

Angle of elevation is 78°:

Now that we have that we can solve for the height from the point of 20ft. We use the same formula, because we are looking for the opposite, given the adjacent.

$tan\theta= \dfrac{opposite}{adjacent}$

$Tan78 = \dfrac{opposite}{74.64ft}$

$(74.64ft)(Tan78) = opposite$

351.16ft = Opposite

Now that's the height from the top of the first building. To get the total height of the building we just add the 20ft.

351.16ft + 20 ft = 371.16ft

<em>The building across the street is 371.16 ft tall.</em>

5 0

3 years ago

Does does jupiter mars and saturn have hydrogen and helium in their atmosphere

miss Akunina [59]

Jupiter and saturn have hydrogen + helium. mars, like venus, their atmosphere have co2 + nitrogen

4 0

3 years ago

You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f

ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

Finding the velocity the corn was moving at from $s=vt+0.5at^{2}$

where s = length of stick, t = time, a = acceleration due to gravity

$s=vt+0.5at^{2}$

1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

1 = 0.121v + 0.0717

1 - 0.0717 = 0.121v

v = 7.67 m/s

Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

v = final velocity = 7.67 m/s

u = initial velocity = 0 m/s since it was initially at rest

a = acceleration due to gravity

t' = time taken to fall to the top of the stick

7.67 = 0 + (9.8 x t')

t' = 7.67 / 9.8 = 0.78 s

using the time above to find the distance between the branch the corn falls from and the top of the stick using $s=vt+0.5at^{2}$ where:

s = distance

v = initial velocity = 0 m/s since it was initially at rest

t = time = 0.78 s

a = acceleration due to gravity = 9.8

s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

s = 2.98 m

Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

2.98 + 2.07 = 5.05 m

5 0

3 years ago