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denis23 [38]
3 years ago
8

A ball is thrown vertically upwards with a velocity of 20 m s −1 from the top of a multistorey building of 25 m high. How high w

ill the ball rise from top of the building? (Take g = 10 m s
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

20m

Explanation:

How high the ball rise from top of the building is the same as the maximum height reached by the ball

using equation of motion under gravity

V^2=U^2+2gs

making s the subject

U^2/2g

20^2/2×10=20m

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Infer the direction of the net force acting on a car as it slows down and turns right.
Kobotan [32]
Net force would be towards the right and back (opposite direction of motion) since it's slowing down (decelerating) and turning right.
6 0
3 years ago
Read 2 more answers
On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

42 m/s, negative direction (to the west).

5 0
3 years ago
A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilomet
pshichka [43]

Answer:

The average speed for the entire run is 12 km/h.

Explanation:      

The average speed is given by the following equation:

\overline{v} = \frac{d_{T}}{t_{T}}

Where:

d_{T}: is the total distance

t_{T}: is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

d_{T} = 13 km + 5 km = 18 km

t_{T} = 1 h + \frac{1}{2} h = 1.5 h

Hence, the average speed is:

\overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!                                                                                      

3 0
3 years ago
What is the total current for the circuit? (must include unit - A) I WILL GIVE BRAINLIEST!
Iteru [2.4K]

Answer:2 amperes

Explanation:

Voltage=120v

Total resistance=15+15+30

Total resistance=60 ohms

Current=voltage ➗ resistance

Current=120 ➗ 60

Current=2 amperes

3 0
3 years ago
a student pushes a 0.500 kg trolley along a frictionless surface and accelerates it from rest to 4m/s. how much kinetic energy d
aalyn [17]
  • mass=m=0.5kg
  • velocity=4m/s

\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2

\\ \sf\longmapsto KE=\dfrac{1}{2}(0.5)(4)^2

\\ \sf\longmapsto KE=0.25(16)

\\ \sf\longmapsto KE=4J

7 0
2 years ago
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