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mr_godi [17]
3 years ago
10

Read the excerpt from "Introduction to Poetry" by Billy Collins. or walk inside the poem's room and feel the walls for a light s

witch. How does this metaphor reveal Collins’s message? The metaphor suggests that poetic themes are serious and dark. The metaphor suggests that readers should explore poems in depth. The metaphor insists that readers should move about while reading. The metaphor insists that one must know the poet to understand the poem.
Physics
2 answers:
faust18 [17]3 years ago
5 0

Answer:

D

Explanation:

Well someone has to understand the Poet Lol.

:) hope i helped

liubo4ka [24]3 years ago
5 0

Answer:

d

Explanation:

hi

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Which type of wave is more dangerous for humans? Microwaves or x-rays?
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X- rays. It can damage living tissue
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Find the mass of a 52.2N bucket.​
Goshia [24]

Answer:

m = 5.22 kg

Explanation:

The force acting on the bucket is 52.2 N.

We need to find the mass of the bucket.

The force acting on the bucket is given by :

F = mg

g is acceleration due to gravity

m is mass

m=\dfrac{F}{g}\\\\m=\dfrac{52.2}{10}\\\\=5.22\ kg

So, the mass of the bucket is 5.22 kg.

3 0
3 years ago
An apparatus like the one Cavendish used to find G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.
Ber [7]

Answer:

The magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N.

Explanation:

Given that,

Mass of first lead ball, m_1=5.2\ kg

Mass of the other lead ball, m_2=0.046\ kg

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N

So, the magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N. Hence, this is the required solution.

5 0
3 years ago
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Anna007 [38]

Answer:

Power=V\, I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation:

Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I

Notice that we replaced the quotient representing charge per unit of time (Q/t) by the actual current running through the circuit.

This corresponds to the second option shown in the question: "Voltage times amperage".

6 0
4 years ago
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