Please answer and show Work
2 answers:
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I hope this helps so the first one should be right
Answer:
17/5
Step-by-step explanation:
If cosθ = 12/13, find (1+cotθ)
As shown in the diagram attached,
Cotθ = 1/tanθ = adjacent/opposite
From the diagram attached,
cotθ = 12/a................... Equation 1
But we can find the value of a by using pythagoras theorem
13² = 12²+a²
169 = 144+a²
a² = 169-144
a² = 25
a = √25
a = 5.
Substitute the value of a into equation 1
Therefore,
cotθ = 12/5
(1+cotθ) =(12/5)+1 = (5+12)/5
(1+cotθ) = 17/5
Answer:
Q1
slope=0.16
intercept=30.2
Q2
78.2
Q3
36%
Step-by-step explanation:
Question 1
We are given that
xbar=280
sx=30
ybar=75
sy=8
r=0.6
The regression line can be written as
y=a+bx
a=intercept
b=slope
where
and
b=0.6*(8/30)
b=0.16
a=75-0.16*280
a=30.2
Thus,
slope=0.16
intercept=30.2
Question 2
The regression line in the given scenario
y=30.2+0.16x
Julie pre exam total before the exam was 300.
y=30.2+0.16*300
y=30.2+48=78.2
So, the predicted final exam score of Julie is 78.2.
Question 3
R² denotes the variation in dependent variable y explained by the linear relationship of x and y.
R²=0.6²=0.36
Thus, the proportion of the variation in final exam scores that is explained by the linear relationship between pre-exam scores and final exam scores is 36%.