Given the unbalanced equation: ___ca(oh)2 + ___(nh4)2so4 → ___caso4 + ___nh3 + ___h2o what is the sum of the coefficients when t
2 answers:
<span>Ca(OH)2 + (NH4)2SO4 </span>→<span> CaSO4 + 2NH3 + 2H2O
That is the balanced equation.
The coefficients represent the amount of moles for that reactant. There is 1 mole of Calcium Hydroxide, 1 mole of Ammonium Sulfate, 1 mole of Calcium Sulfate, 2 moles of Ammonium, and 2 moles of water.
Now add all the coefficients/moles.
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The answer is 7 coefficients.
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That is the balanced equation.
The coefficients represent the amount of moles for that reactant. There is 1 mole of Calcium Hydroxide, 1 mole of Ammonium Sulfate, 1 mole of Calcium Sulfate, 2 moles of Ammonium, and 2 moles of water.
Now add all the coefficients/moles.
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The answer is 7 coefficients.
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Answer:
-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.
Explanation:
Mass of nitrogen triiodide = 20.0 g
Moles of nitrogen triiodide =
According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :
-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.