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BabaBlast [244]
3 years ago
9

What is biological oxygen demand

Chemistry
2 answers:
Novosadov [1.4K]3 years ago
7 0
<span> is the amount of </span>dissolved oxygen<span> needed by aerobic biological organisms to break down organic material present in a given water sample at certain temperature over a specific time period. </span>
jek_recluse [69]3 years ago
5 0

Hey there!!

Biological Oxygen demand is the amount of dissolved oxygen needed  by aerobic biological organisms to break down organic material present in a given water sample at certain temperature over a specific time period.

Hope this helped you and have a fantastic day! (:

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7) Muscles work to lift a bone in your arm by contracts and relaxes to<br><br><br>help please <br>​
Andru [333]

Answer:

By contracting, muscles pull on bones and allow the body to move. When you want to bend your elbow, your biceps muscle contracts, and, at the same time, the triceps muscle relaxes. The biceps is the flexor, and the triceps is the extensor of your elbow joint.

Explanation:

yeah, hope it helps a little. :)

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3 years ago
Which of these is correct?
Viktor [21]

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Explanation:

if you calculate it it will be 1.89

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2 years ago
Question 3 (5 points)
Daniel [21]

Answer:

332.918g O2

Explanation:

I'm having some issues with the work however, your final answer should be 332.918g O2

Hope this helped!

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3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP ME I NEED HELP!
AleksAgata [21]
I think the answer would be trenches but I’m sorry if I’m wrong
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3 years ago
Cr2o2−7(aq)+i−(aq)→cr3+(aq)+io−3(aq) (acidic solution) express your answer as a chemical equation. identify all of the phases in
Rashid [163]
<span>Answer: Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either. Start with your 2 half reactions: I- --> IO3- Cr2O72- --> 2 Cr3+ Balance O by adding H2O: I- + 3 H2O --> IO3- Cr2O72- --> 2 Cr3+ + 7H2O Balance H by adding H+: I- + 3 H2O --> IO3- + 6 H+ Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O Balance charge by adding e-: I- + 3 H2O --> IO3- + 6 H+ + 6 e- Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give: Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
4 0
3 years ago
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