45 g Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.
Answer:
please where is the Gibb free energy to indicate if its exothermic or endothermic reaction but the chemical equation is homogeneous one.
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
Answer:
54.72 g
Explanation:
Mass = ?
Volume = 5.61 L
Pressure = 5.66 atm
Temperature = 311 K
The relationship between these equations is given by the ideal gas equation;
PV = nRT
where R = gas constant = 0.0821 atm L K-1 mol-1
n = PV / RT
n = 5.66 * 5.61 / (0.0821 * 311 )
n = 1.2436 mol
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g
KMnO4 has the incorrect set of oxidation numbers. Whenever there is an alkali metal, it has an oxidation number of +1. As you can see, K is said to have an oxidation number of +2, so it is incorrect.
