1. The molar mass of Fe2(CO3)3 is 291.72 g/mol. This means that 45.6 g is equivalent to 0.156 mol. Dividing by the 0.167 L of water gives a solution of 0.936 M.
2. Multiplying (0.672 M)(0.025 L) = 0.0168 mol. The molar mass of Ni(OH)2 is 92.71 g/mol, so multiplying by 0.0168 mol = 1.56 grams. Therefore you would need to dissolved 1.56 g of Ni(OH)2 into 25 mL of water.
3. Fe2(CO3)3 + Ni(OH)2 --> Fe(OH)3 + NiCO3Balancing: Fe2(CO3)3 + 3Ni(OH)2 --> 2Fe(OH)3 + 3NiCO3The reaction quotient is:[Fe(OH)3]^2 * [NiCO3]^3 / [Fe2(CO3)3][Ni(OH)2]^3= (0.05)^2 * (1.45)^3 / (0.936)(0.672)^3= 0.0268Since this is < 1, it implies that the reactants are favored at equilibrium.
(All) 3.17 pots × 16 beans/1 pot = 51 beans, the answer is rounded.
Answer:
A. She can run the same distance in a shorter amount of time.
Explanation:
Speed can be computed with the formula:
Where:
v = speed
d = distance
t = time
So if you look at the formula, distance there tells you how far an object has traveled, and the time tells us how long it took to cover that distance. As you can see, speed and time are <u>inversely proportional. </u>This means that as one goes up, the other goes down. So if we reduce time travelling a certain distance, the speed increases.
So, based on the given information, scientists were capable of using models to represent the shape of the structure. The shape resembled a soccer ball.
However, scientists were not able to represent color, size, bonding or chemical structure of the molecules, they only resembled the shape of the submicroscopic matter.
Based on the above, the function this model served in science is:
The model presents a visual picture of submicroscopic matter.
Answer:
Hi AP Chemistry student. It seems this experiment is impossible. Sterling Silver cannot be separated so easily with this pathetic equipment. However, if one were to carry this experiment out, I would assume they would need to put the alloy in the graduated cylinder and then somehow filter the silver out through filter paper or Buchner funnel. taking the mass with a stir rod is also helpful for the mass percent calculation. I hope this helps you out, good luck in Mrs. Fischer's class :)
Explanation:
