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Evgesh-ka [11]
3 years ago
11

A student found the mass of an object to be 26.5 g. To find the volume, the student submerged the object in a graduated cylinder

of water. Submerging the object in the water in the graduated cylinder increased the water level by 24.1 mL. The density of the object is
Question 17 options:

A) 0.909 g/mL.

B) 1.1 g/mL.

C) 1.10 g/mL.

D) 1.0906 g/mL.
Chemistry
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer: The density of the object is 1.10 g/ml

Explanation: Density of object = ?

Mass of object = 26.5 g

Volume of object = volume of water displaced = 24.1 ml

Putting values in above equation, we get:

Density: \frac{26.5g}{24.1ml}  = 1.10g/ml

Thus density of the object is 1.10 g/ml

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You need to prepare 150 mL of 0.1 M solution of silver chloride. How much silver chloride is required?
Rudiy27

Answer:

amount of silver chloride required is 0.015 moles or 2.1504 g

Explanation:

0.1M AgCL means 0.1mol/dm³ or 0.1mol/L

1L = 1000mL

if 0.1mol of AgCl is contained in 1000mL of solution

then x will be contained in 150mL of solution

cross multiply to find x

x = (0.1*150)/1000

x= 0.015 moles

moles of silver chloride present in 150 mL of solution is 0.15 moles

To convert this to grams, simply multiply this value by the molar mass of silver chloride

molar mass of silver chloride AgCl =107.86 + 35.5

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mass of AgCl = moles *molar mass

                       =0.015*143.36

                        =2.1504g

                        =

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For the reaction of aqueous strontium chloride and lithium sulfate, write the balanced molecular equation
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Explanation:

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