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raketka [301]
3 years ago
12

Line segment XY has endpoints X(5,7) and Y(-3,3)

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

y=-2x+7

Step-by-step explanation:

line segment xy has endpoints x(5 7) and y(-3 3)

for the equation of the perpendicular bisector of line segment xy

slope of line segment xy = 7-3 / 5+3

= 4/8

=1/2

so slope of perpendicular bisector is -2

as m1m2= -1 or m1= -1/m2

As perpendicular bisector goes through midpoint of xy , let's find midpoint of xy

midpoint(x,y) = (5-3 / 2 , 7+3 / 2)

=(2/2, 10/2)

=(1,5)

find the equation of line(perpendicular bisector) passing through (1,5) and the slope -2

y-5 = -2(x-1)

y-5 =-2x+2

y=-2x+7

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<img src="https://tex.z-dn.net/?f=%287x%5E%7B2%7D%29%282x%5E%7B4%7D%29%28-5x%29" id="TexFormula1" title="(7x^{2})(2x^{4})(-5x)"
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(7x^{2})(2x^{4})(-5x)

= 7(2)(-5)(x^{2})(x^{4})(x)

= -70(x^{7})

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