Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
Answer:
The answer to your question is below
Step-by-step explanation:
5) 2x² -7x + 34
x + 5 2x³ + 3x² - x + 1
-2x³ -10x²
0 - 7x² - x
+7x² +35x
0 +34x + 1
-34x - 170
0 - 160
Quotient = 2x² - 7x + 34
Remainder = -160
6) 2x² - 3x + 1
3x + 1 6x³ - 7x² + 0x + 2
-6x³ -2x²
0 -9x² + 0x
+9x² +3x
0 +3x + 2
- 3x - 1
0 + 1
Quotient = 2x² - 3x + 1
Remainder = 1
Answer:
25
Step-by-step explanation:
30-60-90 Triangles
short leg = x
long leg = x
hypotenuse = 2x
Haoyu, I'm telling Ms. Mak about your behavior. Expect not to see tomorrow, you were cheating on the math test. I will also contact your parents. Reply to me immidetly if you do not want to get exposed to everyone.
<span>I think you know by now that I strongly encourage everyone to shoot a proper round and whatever the score is, to submit it to our Records Officer, Giles Conn. Think of it as an annual competition (a) to wear him out, and (b) to see if we can altogether, beat last year's tally. Also, for the outdoor season rounds, you can have a go at achieving the St Wilfred trophy. I've won it 3 years running (last year jointly with Terry Skinner), but they wouldn't let me keep it this time, sadly.</span>
