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Deffense [45]
2 years ago
9

HELP PLSPLSPLS

Mathematics
1 answer:
ddd [48]2 years ago
3 0

all "atomic" or constituent statements are true

at least one "atomic" or constituent statement is true

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How do I solve the equation 15plus b equals 23
kompoz [17]
15+B=23 

subtract 15 from both sides 

-15+15+B=23-15

15 cancels out on the left and the answer is:

B=8

Hope this helps :)

8 0
3 years ago
Pls helpppp reall need help like bad im dumb with no brain cells right now
gulaghasi [49]

Answer:

3m/day

Step-by-step explanation:

1) Subtract 4 from 22--22-4=18

2) Divide 18 by 6-- 18/6=3

3) That means that she ran 3 miles for the 6 remaining days

3 0
3 years ago
A Fraction of the Fair
Irina18 [472]

Answer:

2. 3 3/4

3. 1 2/4

4. 4 days

5. new value = 3/4

Step-by-step explanation:

2. 3 3/4

3. 1 2/4

4. 4 days

5. smallest = 1 2/4

    largest = 3 3/4

largest - smallest = 3

if the new value = 3/4

3 3/4 - 3/4 = 3

7 0
2 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
Marsha went out to dinner with four of her
Vanyuwa [196]

Answer:

$86

Step-by-step explanation:

You multiply 21.50 times 4

4 0
2 years ago
Read 2 more answers
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